登录
首页 » matlab » code_decode

code_decode

于 2013-11-25 发布 文件大小:3KB
0 149
下载积分: 1 下载次数: 2

代码说明:

  使用matlab中的GUI设计的译码器,配有适当的注释,适合初学者。(The GUI design using matlab decoder, with appropriate comments, suitable for beginners.)

下载说明:请别用迅雷下载,失败请重下,重下不扣分!

发表评论

0 个回复

  • jlgd
    自编的捷联惯导程序,四元素的初值及更新、速度和位置的更新及解算(Self SINS program, the four elements of the initial and updated velocity and position updates and the Solution)
    2011-06-13 16:03:27下载
    积分:1
  • gray_scale_half
    MatLab Gray Scale by Half
    2014-10-18 06:16:15下载
    积分:1
  • gaoyang_v69
    滤波求和方式实现宽带波束形成,用MATLAB实现动态聚类或迭代自组织数据分析,匹配追踪和正交匹配追踪。( Filtering summation way broadband beamforming, Using MATLAB dynamic clustering or iterative self-organizing data analysis, Matching Pursuit and orthogonal matching pursuit.)
    2016-05-12 13:47:09下载
    积分:1
  • lfm_ambg
    线性调频信号的波形和其模糊函数,以及其模糊函数的图形。直观表示该信号的模糊函数(LFM waveform and the ambiguity function, and its ambiguity function of the graphics. Visual representation of the signal ambiguity function)
    2020-11-08 14:39:47下载
    积分:1
  • test
    测试对于整个测试集的识别率对于测试集合的识别率(Test for the entire test set recognition rate)
    2010-11-29 15:16:09下载
    积分:1
  • annealing-algorithm
    模拟退火算法matlab源程序,可用于网络流量数据的分析(Simulated annealing algorithm matlab source code, can be used for the analysis of network traffic data)
    2011-10-04 16:52:33下载
    积分:1
  • mohuPID
    模糊PID控制的matlab仿真模型,已通过试验,课成功运行,主要是用来控制机器人自动导航。(Matlab simulation model based on fuzzy PID control, has passed the test, lesson successful operation, is mainly used to control the robot autonomous navigation.)
    2013-12-04 14:51:28下载
    积分:1
  • canchadj
    残差定阶方法的例程,附模型所需的数据,希望对大家有用。(The residual method of order determination routine, with the required data model, the hope that useful.)
    2012-05-10 11:23:55下载
    积分:1
  • ImageFusion_DWT
    遥感图像融合方法中基于小波变换的融合方法matlab代码,同时附上测试用的遥感影像(Remote sensing image fusion method based on wavelet transform. It s matlab code, with remote sensing images used for testing)
    2020-10-08 10:17:37下载
    积分:1
  • c
    说明:  约瑟夫问题的实现:设有n个人围坐在圆桌周围,现从某个位置m(1≤m≤n)上的人开始报数,报数到k的人就站出来。下一个人,即原来的第k+1个位置上的人,又从1开始报数,再报数到k的人站出来。依此重复下去,直到全部的人都站出来为止。试设计一个程序求出出列序列。(Joseph realized the problem: There are n people sitting around the round table, is from a position of m (1 ≤ m ≤ n) reported on the number of people began to be reported to the k number of people to come forward. The next person, that is, the original positions on the first k+1 people, and from the number reported at 1, then the number reported to the k to stand up. So repeat this until all the others can stand up. Try to design a program derived from the column sequence.)
    2011-03-23 15:36:50下载
    积分:1
  • 696518资源总数
  • 105540会员总数
  • 37今日下载