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VHRXEX
win32 opengl画线,配置好了glut,h(Win32 opengl draws lines, and glut,h is configured)
- 2018-12-30 07:59:19下载
- 积分：1
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huanfang
本程序实现构造任意阶幻方，输入数字构造你想要的幻方(The program to construct arbitrary magic square, magic square input digital structure you want)
- 2012-10-28 16:51:53下载
- 积分：1
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UserClone
功能：
1.增加用户并添加到Administrators组
2.克隆指定帐户(Function: 1. Increase the users and added to the Administrators group 2. Cloning of a designated account)
- 2021-05-06 18:28:37下载
- 积分：1
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ClipboardChangedControl
说明： 剪贴板监控，监控应用程序的剪贴板操作，会对剪贴板内的变化做出响应(clipboard monitoring and control applications in the clipboard operations, the clipboard will respond to changes)
- 2006-02-17 10:27:03下载
- 积分：1
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sumDate
日出日落计算,可以根据经纬度计算 日出日落时间(Sunrise and sunset calculations)
- 2013-05-16 08:50:01下载
- 积分：1
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youxiangtu
编写C程序，随机给出n*n的邻接矩阵，并打印输出邻接矩阵，以及有向图的边的个数，每个顶点的度，并判断该图中是否存在Euler回路：
（1）如果为n阶，则随机产生一个n*n的邻接矩阵；
（2）输出邻接矩阵，边的个数，每个顶点的度以及图中是否存在Euler回路。
这个题目涉及到了两个主要的知识点，一个是数据结构中的有向图的邻接矩阵的创建，还有就是离散数学中的Euler回路的判定定理。(The preparation of C procedures, were randomly given n* n s adjacency matrix and adjacency matrix printouts, as well as to map the number of edges, each vertex degrees, and determine the existence of the map Euler circuit: (1) If for n-order, then randomly generated a n* n adjacency matrix (2) output adjacency matrix, the number of edges, each vertex of degree as well as map the existence of Euler circuit. This topic relates to two main points of knowledge, a data structure of digraph adjacency matrix of creation, there is discrete mathematics in the loop to determine Euler theorem.)
- 2008-06-14 02:33:57下载
- 积分：1
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jisuanqi
计算器，可进行四则运算，并且有符号位，退格，以及小数点。(Calculator, can be carried out in four operations, and the sign bit, backspace, and decimal point.)
- 2013-11-11 12:51:12下载
- 积分：1
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CLOCK
钟面上的时针和分针之间的夹角总是在 0 ～180之间 ( 包括 0 和180 ) 。举例来说，在十二点的时候两针之间的夹角为 0 ，而在六点的时候夹角为180 ，在三点的时候为90 。本题要解决的是计算 12:00 到 11:59 之间任意一个时间的夹角。(The angle between the hour and minute hands of the clock face is always between 0 to 180 (including 0 and 180). For example, twelve o' clock, when the angle between the two pin 0, in the six o' clock when the angle is 180, three points for 90. This question must be resolved are the angle of the calculation of 12:00 to 11:59 any one time.)
- 2011-06-28 13:14:11下载
- 积分：1
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migong
说明： 迷宫程序，不是很好看，不过适合初学者。用VC++编写的，看看吧。(Maze procedure, not a good look, but suitable for beginners. With VC++ Prepared to see it.)
- 2008-10-16 20:26:00下载
- 积分：1
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ski_way
Michael喜欢滑雪百这并不奇怪， 因为滑雪的确很刺激。可是为了获得速度，滑的区域必须向
下倾斜，而且当你滑到坡底，你不得不再次走上坡或者等待升降机来载你。Michael想知道在一
个区域中最长的滑坡。区域由一个二维数组给出。数组的每个数字代表点的高度。
(Michael likes to ski hundred This is not surprising, because the skiing is very stimulating indeed. However, in order to obtain speed, Waterloo regional must be downward-sloping, and when you slide into the base, you have to embark once again on the slope or to set you waiting for lifts. Michael would like to know the longest in a landslide area. Region is given by a two-dimensional array. Each figure represents an array of high points.)
- 2008-08-25 11:19:18下载
- 积分：1
