登录
首页 » Visual C++ » jose

jose

于 2015-01-09 发布 文件大小:1KB
0 228
下载积分: 1 下载次数: 5

代码说明:

  约瑟夫环(约瑟夫问题)是一个数学的应用问题:已知n个人(以编号1,2,3...n分别表示)围坐在一张圆桌周围。从编号为k的人开始报数,数到m的那个人出列;他的下一个人又从1开始报数,数到m的那个人又出列;依此规律重复下去,直到圆桌周围的人全部出列。通常解决这类问题时我们把编号从0~n-1,最后结果+1即为原问题的解。 (Josephus (Josephus problem) is the application of a mathematical problem: Given n individuals (with numbers 1,2,3 ... n respectively) sitting around a round table. From the number of people gettin k, number of the m man out of the line he s the next person and a number of gettin number to m the man was out of the line and so the law is repeated until the round table were all out of the column. We numbered 0 ~ n-1, the final result is the original problem solution+1 usually solve these problems.)

下载说明:请别用迅雷下载,失败请重下,重下不扣分!

发表评论

0 个回复

  • linked
    关于二叉树的一些相关代码,运用链表的形式,求二叉树的高度,结点个数以及叶节点个数(Some of the relevant code on the binary tree, using a linked list, find the height of a binary tree, the number of nodes, and the number of leaf nodes)
    2013-02-03 11:10:07下载
    积分:1
  • hellow4
    序列二次规划算法,能求解包含约束和无约束的问题,非常方便。(Sequential quadratic programming algorithm to solve constrained and unconstrained contain the problem, very convenient.)
    2021-01-08 18:18:51下载
    积分:1
  • Nqueen
    n皇后问题构造法实现,比起启发式修补运行时间较长。(n Queen realize the issue of construction method, compared to a longer run-time heuristic repair.)
    2008-05-16 12:45:32下载
    积分:1
  • Subset
    说明:  子集和数问题.rar,用C++写的,可以运行(Subset of several problems. Rar, written in C++, you can run)
    2010-04-16 17:42:12下载
    积分:1
  • d
    有助于c++的初学者在平日的学习中更好的学习(Contribute to better learning c++ beginners learning on weekdays)
    2013-11-29 14:32:18下载
    积分:1
  • migong
    简单的迷宫问题,有点土,还望大家多指点指点,在此感激不尽。(????? mad spasm, ? Tang Gao, ? oligonucleotide ??? Ning Ning ? ?, Hitomi ?????.)
    2008-07-05 00:11:37下载
    积分:1
  • yuyundonghui
    参加运动会的 个学校编号为 。比赛分成 个男子项目和 个女子项目,项目编号分别为 和 。由于各项目参加人数差别较大,有些项目取前五名,得分顺序为7,5,3,2,1;还有些项目只取前三名,得分顺序为5,3,2。写一个统计程序产生各种成绩单和得分报表。 2、要求产生各学校的成绩单,内容包括各校所取得的每项成绩的项目号、名次(成绩)、姓名和得分;产生团体总分报表,内容包括校号、男子团体总分、女子团体总分和团体总分。 3、测试数据:对于 , , ,编号为奇数的项目取前五名,编号为偶数的项目取前三名,设计一组实例数据。 (The school serial number participating in Games is. Competition divides into men s event and women s event , the project serial number parts for the sum. The difference is bigger since every project participates in a number , some projects choose the first five , score order is 7 , 5 , 3 , 2 , 1 Still have some of projects taking the first three places , score only being 5 , 3 , 2 in proper order. Write a form for report counting procedure producing the various school report card and score. 2, demands the school report card producing every school , content includes every achievement project number , position in a name list (achievement) , full name and score per got by school Produce the group total points form for report , content including the school number , male person group total points , woman group total points and group total points. 3, testing data: Be that the odd number project chooses the first five to the serial number, the serial number is that the even number project c)
    2009-04-07 22:40:37下载
    积分:1
  • tree
    使用非递归的方法遍历二叉树,可以直接运行。( Non-recursive binary tree traversal.)
    2013-12-04 16:08:43下载
    积分:1
  • b
    说明:  定义一个类SortArray继承自MyArray,在该类中定义函数sort实现排序功能。 定义一个类ReArray继承自MyArray,在该类中定义函数reverse实现逆转功能。 定义一个类AverArray继承自MyArray,在该类中定义函数Aver实现求解整数的平均值。 定义NewArray类,同时继承了SortArray、ReArray和AverArray,使得NewArray类的对象同时具有排序、逆转和求平均值的功能。在继承的过程中声明为虚基类,体会虚基类在解决二义性问题中的作用。 (Define a class SortArray inherited from MyArray, defined in the class sorting function sort implementation. Define a class ReArray inherited from MyArray, define the function in reverse to achieve such reversal function. Define a class AverArray inherited from MyArray, defined in the class to solve integer function Aver achieve the average. Defined NewArray class, and inherits SortArray, ReArray and AverArray, making the object of both NewArray class sorting, reversing, and the mean value of the function. In the process of succession declared as virtual base classes, virtual base class experience in resolving ambiguities of the role.)
    2010-06-02 02:13:03下载
    积分:1
  • 1
    说明:  数据结构中的顺序表,是其中的一个重要组成部分(The order of the table data structure is an important component of which)
    2011-05-06 14:34:13下载
    积分:1
  • 696518资源总数
  • 106161会员总数
  • 5今日下载