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KalmanFilter
说明： 主要是介绍卡尔曼滤波器的原理，并形象地说明了实现过程，最后用matlab实现了这一原理。(Mainly to introduce the principle of Kalman filter, and vividly illustrates the realization of the process, and finally use matlab to achieve this principle.)
- 2008-11-24 16:58:28下载
- 积分：1
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mpt_ver262
多参数规划工具箱用来计算约束线性及分段仿射系统控制器的最优显式解。(multi-parametric toolbox(MPT)is a matlab toolbox for computing explicit optimal orsub-optimal feedback control laws for constrained linear and piecewise affine systems. )
- 2009-12-01 10:28:56下载
- 积分：1
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battorworth
基于双线性变换法的MATLAB高通数字IIR滤波器的设计 仿真用MATLAB来做的(Bilinear transformation method based on the MATLAB high-pass digital IIR filter design and simulation using MATLAB to do the)
- 2011-01-11 15:14:02下载
- 积分：1
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LunarCalendar
说明： 一个简单但是很有意思的代码。可以实现阳历和阴历的转换。并且能够查询阴历。(A simple but very interesting code. Can achieve the conversion solar and lunar calendars. And the ability to check the lunar calendar.)
- 2020-09-12 15:17:59下载
- 积分：1
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NormFitGA
normal fit遗传算法，MATLBA编程。。。。。。。。。。。。(normal fit algorithm, MATLBA programming. . . . . . . . . . . .)
- 2011-05-08 10:56:53下载
- 积分：1
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Main_grating
超结构光纤光栅基本特性，利用matlab进行仿真模拟，计算反射谱和投射普(Super-structure fiber grating basic characteristics
)
- 2012-04-14 15:08:47下载
- 积分：1
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memetic
memetic是一种高效的文化进化计算方法，该范例以Rosenbroek函数为例进行了演示，你也可以加入其它函数进行测试。(memetic cultural evolution is an efficient method of calculating the sample to Rosenbroek function as an example of the presentation, you can also add other functions to be tested.)
- 2011-11-12 02:03:36下载
- 积分：1
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fourier_demo
This demonstration is intended for people who know something about the theory of the discrete Fourier transform, and who would find it helpful to see some its properties demonstrated graphically, using a programming language.
The demonstration shows the form of the Fourier components of a signal in 1-D and in 2-D, and shows how elementary filtering can be applied in the Fourier domain.
- 2011-10-09 17:12:28下载
- 积分：1
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PNcodeacquisition
基于matlab采用匹配滤波器实现的PN码捕获与跟踪，对学习PN码捕获的朋友很有帮助(Matlab using matched filter based on the PN code acquisition and tracking, PN code acquisition in learning helpful friend)
- 2010-08-31 23:16:35下载
- 积分：1
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exercise
根据公式I（n-1）=（1-In）/n 令I11=0计算I1 到I10；
根据公式In=1-nI(n-1) 令I0=0.6321 计算I1到I7；
根据公式X2=a ， 令a=2，计算X的值。(According to the formula
I(n-1)=(1-In)/n ，set I11 equals zero，and count I1 to I10.
According to the formula
In=1-nI(n-1)，set I11 equals zero，and count I1 to I10.
According to the formula X square equals a ，set a equals two ，then calculate X
)
- 2010-05-09 21:54:01下载
- 积分：1
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