登录
首页 » Asm » q1

q1

于 2015-01-18 发布 文件大小:2KB
0 119
下载积分: 1 下载次数: 0

代码说明:

说明:  Pokeface 题目描述 魔术师将一叠扑克顺次在桌上排成一行,初始全部正面朝上。随后,他每次挥一挥衣袖,都会翻转一连串的扑克,改变它们的正反朝向。从古代传下来的规矩,魔术师皆有师傅,他们要随时准备回答师傅的问题。问题形如:目前从第i张扑克牌到第j张扑克牌中,有几张正面朝上? 作为魔术师的助手,你被要求学习程序设计、算法与数据结构。现在,魔术师把这个问题交给了你,你需要编写一个程序,维护相应的数据结构来保存桌子上牌面的情况,同时对于师傅的每一个问题,你要用尽量快的速度计算出答案。 输入 第一行包含三个正整数n、p和q。n表示扑克牌的数量,p表示魔术师的挥一挥次数,q表示师傅的问话次数。 接下来共p+q行,每行包含一个操作,操作分为2种: H i j 魔术师挥一挥,改变了第i张牌到第j张牌的正反 Q i j 师傅问话:截至目前,第i张到第j张牌中有多少张正面朝上 操作中恰好包含p次H操作,q次Q操作,与第一行的p和q吻合。H操作和Q操作的范围均包含边界(即第i张和第j张牌)。 对于每个操作,输入保证1 ≤ i ≤ j ≤ n。 输出 对于每次Q操作,输出一行,包含一个整数,表示问题的答案。 提示:线段树(Pokeface Title Description The magician will stack poker table sequentially in a row, all the initial face-up. He then every wisp will flip a series of poker pros and cons of changing their orientation. The rules handed down ancient times, the master magician Jie, they be ready to answer the teacher s questions. Question of the form: Currently playing cards i to j-card poker, there are a few face-up? As a magician s assistant, you are required to learn programming, algorithms and data structures. Now, the magician put this question to you, you need to write a program to maintain appropriate data structure to hold the cards on the table face the situation, while the master for each question, and you want to use as quickly calculate the answer. Enter The first line contains three positive integers n, p and q. n represents the number of poker, p represents the wave of the magic number, q represents the number of master s questioning. Next, a total of p+ q rows, each containi)

下载说明:请别用迅雷下载,失败请重下,重下不扣分!

发表评论

0 个回复

  • 游戏架构设计与策划基础
    和游戏相关的书籍,一本很不错的书籍,推荐给大家(About game,it is a good book, you can have!!)
    2020-06-23 09:40:02下载
    积分:1
  • FCFS
    先来先服务(FCFS)调度:按先来后到次序服务,未作优化。(First come first serve (FCFS) scheduling: the order of service by first come first served, not for optimization.)
    2012-01-01 13:48:29下载
    积分:1
  • bpnnet_156
    在实际应用中,原始的BP算法很难胜任,因此出现了很多的改进算法。BP算法的改进主要有两种途径,一种是采用启发式学习方法,另一种则是采用更有效的优化算法。本例采用动量BP算法,来实现对网络的训练过程,动量法降低了网络对于误差曲面局部细节的敏感性,有效地抑制网络陷于局部极小。 (In practical applications, the original BP algorithm very difficult to do, so there were a lot of the improved algorithm. BP Algorithm There are two main channels, a heuristic learning method is adopted, another is the introduction of more efficient optimization algorithm. In this case the use of momentum BP algorithm to realize the network training process, momentum method to reduce the network error surface for the local details of the sensitivity of the network effectively inhibited in a local minimum.)
    2008-06-16 20:29:09下载
    积分:1
  • cxht-promotionLove-web
    微信愚人节活动:登录注册发送表白信息,所有信息入库,包括发送者的openId unionid 等,并且统计数量.(WeChat Fool s Day activities: Sign up to send express messages, all information into the library, including the sender s openId unionid, and statistics.)
    2020-10-19 21:37:25下载
    积分:1
  • 视频电话会议全站源码 (价值十万)。测试通过。我非常满意的源序。...
    视频电话会议全站源码 (价值十万)。测试通过。我非常满意的源程序。-video conference call the station source (worth 100,000). Test. I am very satisfied with the source.
    2022-03-01 16:24:34下载
    积分:1
  • 一个免费的用于局域网的消息传送小工具, 您可以用它来取代 Windows自带的 WinPopup.EXE...
    一个免费的用于局域网的消息传送小工具, 您可以用它来取代 Windows自带的 WinPopup.EXE-For a free LAN messaging gadget, you can use it to replace Windows built-in WinPopup.EXE
    2022-05-23 22:47:19下载
    积分:1
  • UDP通信实例,很简单,是在。NET框架下写的
    UDP通信实例,很简单,是在。NET框架下写的-UDP communication examples, very simple in. NET framework written in
    2022-06-16 17:35:05下载
    积分:1
  • DiskCopy
    DOS下装机必准备工具,EXE文件和批处理文件,DOS下以前经常用到的.(DOS must be installed under preparation tool, EXE file and the batch file, DOS under the previously frequently used.)
    2009-11-22 08:16:15下载
    积分:1
  • 最新反译工具,可以完全译你的.net序,自动升级
    最新反编译工具,可以完全编译你的.net程序,自动升级-find IP addr
    2022-01-24 17:33:38下载
    积分:1
  • GetModuleBaseAddress
    How to get Module s base address of windows by vc.(How to get Module's base address of windows b y vc.)
    2006-09-27 19:45:16下载
    积分:1
  • 696524资源总数
  • 103872会员总数
  • 62今日下载