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Walchko-1
Development of a Sliding Mode Control System with Extended Kalman Filter Estimation for Subjugator
- 2010-03-04 16:31:51下载
- 积分：1
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drtoolbox
Dear all find here important tool box for dimension reduction. TOOL box contaion PCA, ICA, LBP, Kernel LDA, Kernel PCA etc
Enjoy!!!!!!!!!!!!!!!!
- 2012-09-10 01:07:43下载
- 积分：1
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proje
MATLAB PROJECT TO SOLVE TRANSPORTATION
- 2010-06-09 00:23:01下载
- 积分：1
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zhijiezhuanjufanghzen
自己用MATLAB仿真的直接转矩控制电机的仿真，大家可以参考一下！(Own use MATLAB simulation of direct torque control of motor simulation, we can refer to!)
- 2011-09-18 21:42:20下载
- 积分：1
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matlab
2009年全国研究生数模竞赛B题matlab程序(2009 National Graduate Mathematical Contest in Modeling B title matlab program)
- 2009-11-04 20:23:33下载
- 积分：1
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GAtoolbox_matlab
GA TOOLBOX USING C++
- 2009-05-02 11:58:40下载
- 积分：1
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rutina
2D fem solver for Octave/matlab
- 2012-05-22 03:14:40下载
- 积分：1
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ByangtiaoSculpt
Matlab实现绘制任意自由曲线，实现Photoshop中的钢笔路径功能，用光顺连接的B样条/贝塞尔曲线实现，鼠标点击生成控制点，拖动形成任意曲线。可描绘多路径，也可旋转、平移、缩放。经调试可用。(Matlab achieve rendering arbitrary free curve, realize the pen path function in Photoshop, with the light of the B spline/Bessel curve, the mouse click to generate control points, drag to form any curve. Can depict many paths, but also can rotate, translation, scaling. Debug available.)
- 2021-01-30 18:48:34下载
- 积分：1
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dcmstart
This simulation demonstrates the starting of a DC motor with automatic starter (5 hp 240V 1200 rpm) rated torque Tr = 30 N.m
The starter is simulated by a speed-dependent
effective armature resistance using a look-up table
- 2010-11-11 16:41:02下载
- 积分：1
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One-dimensional-extremum-problem
说明： 第6章 无约束一维极值问题
所在章节 函数名 功 能
6.1 minJT 用进退法求解一维函数的极值区间
6.2 minHJ 用黄金分割法求解一维函数的极值
6.3 minFBNQ 用斐波那契法求解一维函数的极值
6.4 minNewton 用牛顿法求解一维函数的极值
6.5 minGX 用割线法求解一维函数的极值
6.6 minPWX 用抛物线法求解一维函数的极值
6.7 minTri 用三次插值法求解一维函数的极值
6.8.1 minGS 用Goldstein法求解一维函数的极值
6.8.2 minWP 用Wolfe-Powell法求解一维函数的极值
(Chapter 6 unconstrained extremum problem one-dimensional sections of the functional 6.1 minJT function method for solving one-dimensional with the advance and retreat of the extreme range of 6.2 minHJ function of the golden section method using one-dimensional function of the extreme 6.3 minFBNQ use Fibonacci method one-dimensional function of the extreme 6.4 minNewton Newton method with one-dimensional function with extreme 6.5 minGX one-dimensional secant method to solve the extreme 6.6 minPWX function method for solving one-dimensional parabolic function of the extreme 6.7 minTri method with cubic interpolation one-dimensional function of the extreme 6.8.1 minGS Goldstein method with one-dimensional function of the extreme 6.8.2 minWP Wolfe-Powell method with a one-dimensional extreme value function)
- 2011-04-12 15:51:56下载
- 积分：1
