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1233
分布傅立叶法求解脉冲在光纤中的传输求解非线性薛定谔方程(Fourier method to solve the distribution of pulses in optical fiber transmission for solving nonlinear Schr?dinger equation)
- 2007-10-07 10:22:04下载
- 积分:1
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MATLABfunction-reference-book
matlab常用函数,包含了大多数常用代码,可按需求查阅(Matlab commonly used functions, including the most commonly used code, can according to need to refer to)
- 2013-02-03 22:08:29下载
- 积分:1
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Matlab-Codes
荷兰瓦格宁根大学研究的温室小气候模型,包含17个状态变化和8个控制变量,具有较高的模拟精度(a complete greenhouse microclimate model developed by wagenigen, have 17 state variables and 8 control inputs,and posses precise simulation error)
- 2013-09-15 14:14:32下载
- 积分:1
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QPSK
说明: 描述了采用卷积码的QPSK系统的代码编写,通过运行代码可以看到系统性能(bpsk)
- 2010-03-25 19:57:20下载
- 积分:1
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ucancmusic
它是基于均匀圆阵的非圆信号NC-MUSIC算法的波达方向估计(It is DOA estimation of UCA Based on NC-MUSIC algorithm)
- 2010-12-25 11:42:59下载
- 积分:1
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R_Load
Matlab code to calculate LC load response using simulink
- 2012-03-27 03:09:21下载
- 积分:1
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iir-filter
基于matlab用脉冲响应不变法和双线性变换法实现iir数字滤波器的设计(A design of two ways to realise iir digital filter)
- 2013-05-02 01:39:40下载
- 积分:1
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main
利用参数辨识法提取相关对准参数,从而估计出陀螺漂移和数学平台偏角并进行补偿。仿真结果表明,开路罗经法对准具有较高的对准精度、较好的快速性,能够满足捷联惯导系统在静基座下实现自对准的要求。(Expressions of mathematical platform misalignment angles of the open-loop algorithm are derived and parameter identification method is
used to pick-up the corresponding coefficients from angle measurements in order to identify and compensate gyro drifts and platform misalignment.The simulation results show that the open circuit gyrocompass alignment of SINS can all meet the requirement of SINS initial alignment with high accuracy and quick reaction on static base. thus can meet the high-precision alignment requirement of carrier based inertial navigation system on swinging base.
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- 2014-02-09 15:52:36下载
- 积分:1
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Engine_Simulink
一个简单的发动机模型,大家可以互相学习,这个模型是别人做建立的(A simple engine simulink model )
- 2012-04-15 13:16:45下载
- 积分:1
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swarm-particle-algorithm
对粒子群算法改进的算法,其各性能有很好的改进(Improved particle swarm optimization algorithm, its performance is very good improvement)
- 2011-06-22 10:21:25下载
- 积分:1