-
Poisson-equation
二维泊松方程的定解问题：用5点菱形异步迭代格式求解泊松方程，h=5/4 ,误差s=1e-6
(Differential method for Poisson equation)
- 2015-05-29 20:28:24下载
- 积分：1
-
12408927_G_P算法
说明： 关联维数求解，大组件构建，可以快速得到关联维数的值。(The value of correlation dimension can be obtained quickly by solving the correlation dimension and constructing large components.)
- 2021-04-10 10:00:20下载
- 积分：1
-
Quarter
四分之一圆柱贴体网格的生成，可以调节大小(Fourth cylindrical body-fitted grid generation, you can adjust the size of the)
- 2021-04-03 11:49:05下载
- 积分：1
-
ART2100
一种借助lowtran7计算大气透过率和目标辐射的软件平台ART2100(A program that used for calculate air transferrate and object randience based on lowtran7)
- 2021-05-07 16:49:36下载
- 积分：1
-
arithmetic
arithemetic code on visual c++
- 2009-12-20 18:53:54下载
- 积分：1
-
Euler-method
欧拉法解微分方程方程组，对于变成基础薄弱的人，易于理解，相信会有用处(Euler method for solving differential equations, to become a person, the weak foundation is easy to understand, I believe there will be.)
- 2016-10-02 17:45:07下载
- 积分：1
-
SQUARESQUEEZE
使用Fortran编程，有限差分法计算雷诺方程(Reynolds equation calculated using Fortran programming, finite difference method)
- 2016-10-18 11:16:37下载
- 积分：1
-
SHENGXUE_BEM
求解声学问题的边界元程序，给声学研究的人员很大启发(Solving the problem of acoustic boundary element program, to inspire great acoustic research staff)
- 2011-07-27 06:37:38下载
- 积分：1
-
Stanford
说明： 并联机器人standFord，其数值解及解析解，正解和逆解以及雅可比矩阵及动力学问题分析(Standford series robot, its numerical solution and analytical solution, positive solution and inverse solution, Jacobian matrix and dynamics analysis)
- 2021-01-21 16:41:14下载
- 积分：1
-
fftbianhuan
test1.txt 第一列为时间t，0.001s为步长；第二列为系统的输入信号；第三列为系统的输出信号。
signal_analyzer.m首先将test1.txt 的数据读入workspace，然后进行FFT，分析出两信号的频率，输出对于输入的幅值衰减（db），输出对输入的相位差。(test1.txt the first time as t, 0.001s for the step the second as the system input signal the third as the system output signal. signal_analyzer.m first test1.txt data read workspace, and then proceed to FFT, analysis of the two signals in the frequency, the output for input amplitude attenuation (db), the output of the input phase difference.)
- 2008-12-13 02:19:50下载
- 积分：1
