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AVLTree
好用的平衡二叉树类库，C++类库编写，
好用的平衡二叉树类库，C++类库编写(AVL tree implementation for C++)
- 2009-03-12 12:02:05下载
- 积分：1
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Calender
日历显示，查询1900年后的日历。每一屏显示一年的日历祥情。(Calender dispaling. Acess the calender detail of years after 1900.)
- 2011-12-18 14:57:15下载
- 积分：1
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Set
使用C语言建立带头结点链表实现了集合。并进行了性能上的优化。(Achieve set using C to build list witch head node. And make optimization in performance.)
- 2009-11-18 13:29:05下载
- 积分：1
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2
说明： 用数据结构的遍历，对于小毛驴过河解决实际问题。(Traversing the data structure used for the small donkey across the river to solve practical problems.)
- 2010-06-02 22:50:30下载
- 积分：1
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zz
说明： 图的相关操作：建立图，图的遍历，查找元素，删除元素等(Map-related steps: the establishment of map, graph traversal, find elements, delete elements, etc.)
- 2008-07-25 15:20:23下载
- 积分：1
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cycQueue
单循环链表，用C++实现
提供入队，出队，判断空等方法(Single cycle linked list, with C++ into the team, the team judge waited in vain for methods)
- 2012-10-08 20:02:15下载
- 积分：1
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tree
C语言树的简单实现,介绍了树你前序遍历，树插入与删除节点的实现(C-tree is simple to achieve, before you introduced the tree traversal, tree insert and delete nodes to achieve)
- 2011-01-11 22:19:07下载
- 积分：1
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Circlist_Josephus3_4
循环链表的应用
循环链表的应用
很方便的实现(cycle Chain cyclic chain of convenience Implementation)
- 2006-11-23 19:36:47下载
- 积分：1
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joseph
用链表解决约瑟夫问题。
约瑟夫环是一个数学的应用问题：已知n个人（以编号1，2，3...n分别表示）围坐在一张圆桌周围。从编号为k的人开始报数，数到m的那个人出列；他的下一个人又从1开始报数，数到m的那个人又出列；依此规律重复下去，直到圆桌周围的人全部出列。
其中包括一个实验报告，介绍了编程思路和输出结果截图。(List to resolve Joseph. Josephus is the application of a mathematical problem: Given n individuals (numbered 1, 2, 3, ... n, respectively) sitting around a round table around. From number k people began to count off the number to m the man out of the line his next person and from a number off, the man was out of the line number to m so regularly repeated down until roundtable around of the people all of the columns. Including a lab report describes the programming ideas and output screenshots.)
- 2012-08-27 22:37:52下载
- 积分：1
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KDTreeTest
一个KDtree的程序，包含建树过程和消耗的时间。(A KDtree procedures, including the contribution to the process and time consuming.)
- 2020-12-22 10:29:08下载
- 积分：1
