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pq3
pq快速解耦法解电力潮流 适用于电力潮流计算的初学者 简单明了(pq Solving fast decoupled power flows)
- 2010-03-04 08:40:31下载
- 积分:1
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最小2乘法
Delphi实现最小二乘法,进行多点拟合,目前支持4点拟合(Delphi realizes the least square method and multi-point fitting. At present, it supports four-point fitting.)
- 2020-06-17 19:40:01下载
- 积分:1
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wenoeul
有限差分法求解欧拉方程,weno有限差分法求解欧拉方程。(Euler solved with weno)
- 2021-03-22 20:19:16下载
- 积分:1
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finite-element-analysis
详细介绍了有限元法基础知识,对有限元入门者很有帮助(Details the basics of the finite element method, finite element beginners helpful)
- 2014-04-13 13:55:52下载
- 积分:1
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1
说明: fluent数值计算中在指定单元坐标加入源项的udf(Add source term to cell coordinates in numerical analysis)
- 2018-07-28 10:08:29下载
- 积分:1
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MY_PREDISTORTION
这是一个关于数字预失真功能仿真的matlab程序,效果不错,希望对大家有所帮助。(This is a matlab program about function estimation of digital estimation,and it has a good performance,really hope it can help you.)
- 2012-06-01 11:29:52下载
- 积分:1
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poisson-process-simulation
模拟应用随机过程中时齐泊松和非时齐泊松过程的matlab源代码(matlab code for poisson process)
- 2012-04-11 16:19:44下载
- 积分:1
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11087 统计逆序对
说明: Description
设a[0…n-1]是一个包含n个数的数组,若在ia[j],则称(i, j)为a数组的一个逆序对(inversion)。
比如 有5个逆序对。请采用类似“合并排序算法”的分治思路以O(nlogn)的效率来实现逆序对的统计。
一个n个元素序列的逆序对个数由三部分构成:
(1)它的左半部分逆序对的个数,(2)加上右半部分逆序对的个数,(3)再加上左半部分元素大于右半部分元素的数量。
其中前两部分(1)和(2)由递归来实现。要保证算法最后效率O(nlogn),第三部分(3)应该如何实现?
此题请勿采用O(n^2)的简单枚举算法来实现。
并思考如下问题:
(1)怎样的数组含有最多的逆序对?最多的又是多少个呢?
(2)插入排序的运行时间和数组中逆序对的个数有关系吗?什么关系?
输入格式
第一行:n,表示接下来要输入n个元素,n不超过10000。
第二行:n个元素序列。
输出格式
逆序对的个数。
输入样例
5
2 3 8 6 1
输出样例
5(Set a[0... N-1] is a n array containing n numbers. If there is a [i] > a [j] i n the case of I < j, then (i, j) is a n inversion pair of a array.
For example, has five reverse pairs. Please use the idea of "merge sorting algorithm" to achieve the statistics of inverse pairs with O (nlogn) efficiency.
The number of inverse pairs of a sequence of n elements consists of three parts:
(1) The number of reverse pairs in the left half, (2) the number of reverse pairs in the right half, (3) the number of elements in the left half is greater than that in the right half.
The first two parts (1) and (2) are implemented by recursion. To ensure the final efficiency of the algorithm O (nlogn), how should the third part (3) be implemented?
Do not use O (n ^ 2) simple enumeration algorithm to solve this problem.)
- 2019-01-07 23:52:06下载
- 积分:1
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shiyan4
若矩阵A中的某一元素A[i,j]是第i行中的最小值,而又是第j列中的最大值,则称A[i,j]为矩阵A中的一个鞍点。请写出一个可确定此鞍点位置的算法(如果这个鞍点存在)。(If the matrix A, an element A [i, j] is the minimum value in the i-th row, but is the maximum value of the j-th column, then A [i, j] for the matrix A is a saddle point. Please write a algorithm to determine the position of saddle point (saddle point exists).)
- 2013-01-07 13:16:11下载
- 积分:1
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code
用C++编写的大整数计算的模板,可实现加、减、乘、除、取模等运算,可以通过此源码学习高精度的实现。(Written with C++ template large integer can be realized addition, subtraction, multiplication, division, modulus and other operations, you can achieve high-precision study of this source.)
- 2011-06-05 17:19:32下载
- 积分:1