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exp1_audio_loop
a simple dsk6713c program
- 2010-08-24 13:51:01下载
- 积分:1
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Rayleigh_fading
Rayleigh 信道仿真模型 参考"Autoregressive modeling for fading channel simulation", IEEE Transaction on Wireless Communications, July 2005. (Rayleigh channel simulation model reference Autoregressive modeling for fading channel simulation , IEEE Transaction on Wireless Communications, July 2005.)
- 2008-01-04 09:23:50下载
- 积分:1
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UKF
这是关于UKF(无味卡尔曼滤波算法)算法的matlab程序(This is on the UKF algorithm matlab program)
- 2013-08-13 14:59:13下载
- 积分:1
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MATLAB
matlab编程学习资料,从最基本理论讲解,循序渐进,适用于初学者。(the matlab programming learning materials, from the most basic theory to explain, step-by-step, suitable for beginners.)
- 2012-12-01 17:13:48下载
- 积分:1
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039_bus
bpa环境下,Ieee39节点稳态暂态标准数据(the bpa environment IEEE 39 node Steady State Transient standard data)
- 2021-03-30 12:19:09下载
- 积分:1
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FISHER
里面有两组数据,然后分为训练样本组和测试样本组,都采用fisher准则判定,再对结果惊醒分析(There are two sets of data, and then divided into groups of training samples and test samples group, have adopted guidelines for determining fisher, and then woke up on the results of the analysis)
- 2013-12-19 18:00:33下载
- 积分:1
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EngineeringMatlabProgramming
本书提供了工程中常见问题的解决方法及仿真过程,适合工科师生仿真参考教程。(The book provides engineering solutions to common problems and simulation process, suitable for engineering students and teachers information and guidance simulation.)
- 2009-01-10 16:56:34下载
- 积分:1
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package_emd
经验模态安装工具包,方便好用,大家学学吧(emd empirical mode toolkit)
- 2013-08-26 17:19:07下载
- 积分:1
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ieee754_32
Converts a floating point value to IEEE 754 32 bit binary representation.
Sign Bit: 1
Exp: 2 to 9
Frac: 10:32
Single-precision floating-point format is a computer number format that occupies 4 bytes (32 bits) in computer memory and represents a wide dynamic range of values by using a floating point. In IEEE 754-2008 the 32-bit base 2 format is officially referred to as binary32. It was called single in IEEE 754-1985. In older computers, other floating-point formats of 4 bytes were used.
For example, the 32-bit floating point bit pattern 1 01111101 00101100000000000000000 is interpreted as the following:
(− 1)1 × (1 + 0.34375) × 2(125–127) = -1.34375× 2− 2 = -0.3359375
- 2013-09-07 22:20:32下载
- 积分:1
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get_system_now
此模块可以获取系统的最高权限SYSTEM权限。(This module can obtain the highest authority system SYSTEM privileges.)
- 2015-03-27 22:29:42下载
- 积分:1