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a_jpeg_compression_matlab
It shows what a jpeg compression is all about.
the function implements the DCT transform, using a matrix operator.
note that matlab has a function for the DCT and iDCT transforms
that might be more efficient.
(It shows what a jpeg compression is all abou t. the function implements the DCT transform. using a matrix operator. note that Matlab has a f unction for the DCT and iDCT transforms that mig ht be more efficient.)
- 2007-05-31 16:01:34下载
- 积分：1
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musi111
在不同信噪比情况下的MUSIC的成功概率(In the case of different signal to noise ratio of success probability of the MUSIC)
- 2011-10-31 17:26:26下载
- 积分：1
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PolSAR
全极化SAR图像极化定标算法，适用于星载SAR，包含法拉第旋转角的校正(Polarization polarimetric SAR image scaling algorithm for spaceborne SAR, includes correction of Faraday rotation angle)
- 2014-04-29 10:33:37下载
- 积分：1
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PWMSound
PWMSound.m processing signal digital
- 2009-03-30 15:48:08下载
- 积分：1
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banfangcha.m
matlab的.m文件，对影像计算不同方向的经验半方差,检测某区域的空间异质性(matlab' s. m files, image computing experience of semi-variance in different directions to detect spatial heterogeneity of a region)
- 2011-05-14 21:25:16下载
- 积分：1
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Mobile__obots
机器人导航程序，其中包括粒子滤波，扩展卡尔曼滤波的实现代码。(robot navigation procedures, including the particle filter, extended Kalman Filter codes.)
- 2007-06-13 21:52:42下载
- 积分：1
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chapter2
说明： 《数字图像处理与机器视觉:Visual C++与Matlab实现》2
频率域图像增强,彩色图像处理(" Digital image processing and machine vision: Visual C++ and Matlab to achieve" two frequency domain, image enhancement, color image processing)
- 2010-04-22 08:55:46下载
- 积分：1
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微分方程组的求解
说明： 工程数值计算大气动力学模型的洛仑兹方程工程案例。
计算原理，流程图，程序代码，绘图结果。(Engineering case of Lorentz equation for engineering numerical calculation of atmospheric dynamics model. Calculation principle, flow chart, program code, drawing results.)
- 2021-01-10 12:12:31下载
- 积分：1
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Retinex
彩色图像的多尺度Retinex算法，MSR算法，算法直接可用(Multi-scale Retinex color image algorithms, MSR algorithm, the algorithm can be used directly)
- 2010-10-08 10:08:24下载
- 积分：1
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LDPCcode
利用函数MadHG生成规则LDPC码的校验矩阵H，其行重为6,列重为3,行数为列数一半(行数越大越好)，H中任意两列没有围长为4的圈，并得到H对应的生成矩阵G，可以保证mod(G*H ,2)=0。使用方法为:[H,G] = MadHG(m,n,x),x= 1(得到的G左半部分为单位阵) or 2(G右半部分为单位阵),(use function MadHG Generation rules LDPC check matrix H, re-6, series of three, out for a few half of the number (A bigger the better), H 2 arbitrary no girth of the four circles, H counterparts and with the formation of matrix G, we can be assured of mod (G* H, 2) = 0. To be used : [H, G] = MadHG (m, n, x), x = 1 (the G part of the Left Front units) or 2 (G right half of the units RUF),)
- 2007-05-12 10:49:48下载
- 积分：1
