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2DLDA
人脸表情识别中的2DLDA方法，特定人识别。(Facial Expression Recognition in 2DLDA method of identifying a specific person.)
- 2009-12-24 20:34:05下载
- 积分：1
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cal_dfeec_ipr
基于standford大学cioffi教授的经典算法，计算有线信道的无限冲击响应滤波器系数。(Based on algorithm proposed by Prof. Cioffi, calculate the optimal IIR coefficients for cable channel.)
- 2014-09-19 18:13:03下载
- 积分：1
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crosscouping_synthesis
微波滤波器耦合矩阵综合，
1 根据传输零点位置，回波损耗求出耦合矩阵；
2 从S21 S11多项式出发 综合出耦合矩阵；
3 已知传输零点位置，滤波器阶数，回波损耗画出滤波器的S参数，分别以4阶和八阶滤波器为例。(1synthesize coupling matrix by the transmission zeros, return loss
2 synthesize coupling matrix by S21 S11 polynomial
3 draw the S parameters of the filter by transmission zeros, return loss,order of filter,
Using 4 order and 8 order filter respectively as an example.)
- 2021-03-02 11:19:34下载
- 积分：1
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seismic-signal-procesing
震动信号的预警和过零率计算，需要有自己的原始震动信号(seismic signal processing zero_-pass rate)
- 2015-01-08 09:57:45下载
- 积分：1
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dsb
对于dsb信号波形的仿真。包括时域波形和频域波形图(Dsb signal waveforms for the simulation. Including time-domain waveforms and frequency domain waveforms)
- 2008-05-06 12:03:12下载
- 积分：1
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matlab
主要介绍一些基于matlab开发环境的一些实用的函数程序事例，非常有用(Introduces some of the functions of some practical examples matlab program development environment based on useful)
- 2013-12-25 16:53:04下载
- 积分：1
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imgsteglsba
HI GUYA CHIT UAING MATLAB WE USE METOD LSB PLS CHECK IT VERY SEFULL
- 2013-11-28 22:24:59下载
- 积分：1
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电流环磁场
把区域划分成矩形网格，找到每个网格的中心点，把每个网格当做一个圆环计算每个圆环的磁场，然后调用linprog函数就求出场分布了。不要求你把线圈矩形化，也不要求屏蔽场。(The region is divided into rectangular grids and the center points of each grid are found. Each grid is used as a circle to calculate the magnetic field of each ring, and then the field distribution is called by the linprog function. It does not require you to rectangle the coil, nor does it require shielding.)
- 2021-03-26 15:19:12下载
- 积分：1
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马尔科夫链法预测股票
说明： 这是马尔科夫链预测的一个非常好的例子，值得大家学习与借鉴。(This is a very good example of Markov chain prediction, which is worth learning and using for reference.)
- 2020-12-06 09:39:24下载
- 积分：1
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romberg_method_integration_order8
NUMERICAL INTEGRATION:
Implementation of the routine of order 8 and applied on the function sin(x), 0<=x<=pi
Code is very understodable, and converge very fast.
- 2009-11-26 21:55:13下载
- 积分：1
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