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doa
基于高阶累积量的doa 高阶累积量的估计计算(doa cum)
- 2012-06-20 13:28:43下载
- 积分:1
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qiyizhi
奇异值能量差分谱计算,可用于信号降噪处理(Singular value of the energy difference spectrum calculation can be used for signal noise reduction)
- 2021-03-21 14:29:16下载
- 积分:1
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Excel_GM
用Excel计算灰色预测模型,每个步骤都有,十分详细。(Calculating Grey Prediction Model with Excel)
- 2020-12-14 15:39:14下载
- 积分:1
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UDF_03_Files
用C语言编写的Fluent UDF实例,包含Adjust宏,profile宏等八个实例教程,快速上手(The UDF is for computational fluid dynamics software Fluent, it concludes the Profile.c,the Adjust.c)
- 2019-05-11 00:02:23下载
- 积分:1
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Least-squaresmethod
基于最小二乘法的冗余信息数据融合算法实现(Least-squares method based on redundant information and data fusion algorithm)
- 2009-11-05 23:10:11下载
- 积分:1
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shock_tube_problem
求解激波管问题等产生的偏微分方程组的各种数值算法。(Shock tube problem solving, such as partial differential equations arising from a variety of numerical algorithm.)
- 2009-03-18 19:18:29下载
- 积分:1
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MachineLearning
说明: 机器学习的鸢尾花数据集的应用逻辑回归算法分类(Classification of iris data set by logical regression algorithm)
- 2021-03-22 13:59:32下载
- 积分:1
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Dijkstra
可实现Dijkstra算法,显示起始点到其它各节点的最短距离和路径(Dijkstra algorithm can be implemented to show the shortest distance and path from the starting point to other nodes.)
- 2020-06-25 02:00:02下载
- 积分:1
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single
使用奇异值分解来帮助求解最小二乘问题,特别是在方程系数矩阵不满秩的情况下。(SGELSD computes the minimum-norm solution to a real linear least
* squares problem:
* minimize 2-norm(| b- A*x |)
* using the singular value decomposition (SVD) of A. A is an M-by-N
* matrix which may be rank-deficient.)
- 2009-10-30 16:32:14下载
- 积分:1
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11087 统计逆序对
Description
设a[0…n-1]是一个包含n个数的数组,若在i<j的情况下,有a[i]>a[j],则称(i, j)为a数组的一个逆序对(inversion)。
比如 <2,3,8,6,1> 有5个逆序对。请采用类似“合并排序算法”的分治思路以O(nlogn)的效率来实现逆序对的统计。
一个n个元素序列的逆序对个数由三部分构成:
(1)它的左半部分逆序对的个数,(2)加上右半部分逆序对的个数,(3)再加上左半部分元素大于右半部分元素的数量。
其中前两部分(1)和(2)由递归来实现。要保证算法最后效率O(nlogn),第三部分(3)应该如何实现?
此题请勿采用O(n^2)的简单枚举算法来实现。
并思考如下问题:
(1)怎样的数组含有最多的逆序对?最多的又是多少个呢?
(2)插入排序的运行时间和数组中逆序对的个数有关系吗?什么关系?
输入格式
第一行:n,表示接下来要输入n个元素,n不超过10000。
第二行:n个元素序列。
输出格式
逆序对的个数。
输入样例
5
2 3 8 6 1
输出样例
5(Set a[0... N-1] is a n array containing n numbers. If there is a [i] > a [j] i n the case of I < j, then (i, j) is a n inversion pair of a array.
For example, <2,3,8,6,1> has five reverse pairs. Please use the idea of "merge sorting algorithm" to achieve the statistics of inverse pairs with O (nlogn) efficiency.
The number of inverse pairs of a sequence of n elements consists of three parts:
(1) The number of reverse pairs in the left half, (2) the number of reverse pairs in the right half, (3) the number of elements in the left half is greater than that in the right half.
The first two parts (1) and (2) are implemented by recursion. To ensure the final efficiency of the algorithm O (nlogn), how should the third part (3) be implemented?
Do not use O (n ^ 2) simple enumeration algorithm to solve this problem.)
- 2019-01-07 23:52:06下载
- 积分:1