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PID
最优控制率下的PID控制器参数，使其具有更好的鲁棒性和自适应的能力。(Optimal control rate of PID controller parameters, it has better robustness and adaptive capacity.)
- 2011-07-11 20:58:53下载
- 积分：1
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mutualinfomation
计算脑电等信号的互信息程序，matlab源代码(Calculating the mutual information procedure, matlab source code)
- 2013-01-26 09:58:58下载
- 积分：1
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tutorial10
matlab图像处理的几个程序 P0301：数字图像矩阵数据的显示及其傅立叶变换(Several procedures P0301 matlab image processing: digital image data matrix display and Fourier Transform)
- 2015-03-21 18:32:06下载
- 积分：1
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OSGEarthdm0828
一个完整的osgearth程序，飞机在空中飞行，并用线条标出飞机移动的轨迹，效果见1.jpg.osgearth需要事先完成安装配置等工作(A complete osgearth procedures, aircraft flying in the air, and marked with lines of track aircraft movement, the effect see 1.jpg.osgearth requires prior completion of the installation configuration, etc.)
- 2014-02-05 19:31:56下载
- 积分：1
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C---Cookbook
C ++ CODEBOOK 完整电子版，学习c++必备。(C++ CODEBOOK)
- 2015-01-23 17:20:13下载
- 积分：1
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houzizhaitao
猴子摘桃海滩上有一堆桃子，五只猴子来分。第一只猴子把这堆桃子凭据分为五份，多了一个，这只
猴子把多的一个扔入海中，拿走了一份。第二只猴子把剩下的桃子又平均分成五份，又多了
一个，它同样把多的一个扔入海中，拿走了一份，第三、第四、第五只猴子都是这样做的，
问海滩上原来最少有多少个桃子？(Peach Monkeys on the beach there is a pile of peaches, five monkeys for points. The first monkey peach credentials this heap is divided into five copies, more than one, the monkey to more than one thrown into the sea, took a. The second monkey the rest of the peaches and what the average is divided into five, and there are one, and it is likewise more than one thrown into the sea, took a third, fourth, fifth monkeys are actually doing that , the question on the beach for at least the number of the original peach?)
- 2009-12-24 15:33:40下载
- 积分：1
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zuoye7
第k小元素（分治法） 给定一个线性序列集，要求求出其中指定的第K小的数的值和位置.如给定n个元素和一个整数i，1≤i≤n，输出这n个元素中第i小元素的值及其位置；(First k small element (divide and conquer) Given a set of linear sequence, where the specified requirements determined the K value and the small number of locations, such as a given n elements and an integer i, 1 ≤ i ≤ n, output this is the n elements of the i-th element value and the position of the small )
- 2013-11-16 11:51:31下载
- 积分：1
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5
一道程序编译顺序的考题，涉及到函数调用的先后顺序及运算符号的优先级等问题。下面我展开给你讲。
C的程序编译总是从main函数开始的，这道题的重点在“fun（（int）fun（a+c,b）,a-c）） ”语句。
系统首先要确定最外层 fun()函数的实参，第一个参数的确定需要递归调用fun()函数（不妨称其为内层函数）。内层函数的两个参数分别为x=a+b=2+8=10、y=b=5,执行函数体x+y=10+5=15,于是得外层函数的参数x=15。其另一个参数y=a-c=2-b=-6,再次执行函数体,得最终返回值x+y=15+(-6)=9。 (Compiling together the sequence of test procedures, involving the sequence of function calls and operator symbols, such as the priority problem. Now I give you to start speaking. Procedures for C compiler always start from the main function and at这道题the focus of " fun ((int) fun (a+ c, b), ac)) " statement. System must first determine the most outer layer of fun () function of real parameters, the first parameters of recursive calls required fun () function (may be called the inner function). Inner function separately for the two parameters x = a+ b = 2+8 = 10, y = b = 5, to execute the function body x+ y = 10+5 = 15, then the outer function parameters were x = 15 . Its another parameter y = ac = 2-b =- 6, once again to execute the function body may eventually return the value of x+ y = 15+ (-6) = 9.)
- 2009-03-15 15:36:23下载
- 积分：1
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main
matlab解决0/1线性规划问题NP难题，(matlab solve the 0/1 linear programming problem NP problem,)
- 2011-01-10 10:36:16下载
- 积分：1
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zhajinhua
6603二次开发运营版炸金花，带前后台控制(6603 Golden fried version of the secondary development operations)
- 2014-02-10 10:32:54下载
- 积分：1
