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VoNeumannarchitecture
this is on about thevonumanarchitecture
- 2009-11-17 17:59:11下载
- 积分：1
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DUDA_MATLAB
这里上载的都是DUDA模式识别课程中的各种算法的MATLAB实现，可以参考DUDA的《模式识别》课本，很实用(DUDA uploaded here are in pattern recognition program MATLAB implementation of various algorithms, see DUDA of " pattern recognition" of textbooks, very useful)
- 2010-11-09 16:49:57下载
- 积分：1
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MIMO_OFDMbasedonLS
说明： MIMO-OFDM基于LS方法的几种滤波方法的比较(MIMO-OFDM-based LS method of comparison of several filter)
- 2010-04-20 09:50:10下载
- 积分：1
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fractional_delay_FIR
matlab设计小数延时滤波器：滤波器长度,期望延迟量可调整(matlab design fractional delay filter: filter length, adjustable delay expected)
- 2014-06-18 17:09:43下载
- 积分：1
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poisson
poisson equation solve
- 2011-08-10 22:17:01下载
- 积分：1
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matlab-xju
说明： Matlab在数字信号处理的应用,xju的教学ppt,很不错.(Matlab in digital signal processing applications, xju teaching ppt, very good.)
- 2006-04-08 11:02:10下载
- 积分：1
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nolog
images and logfile messages
- 2013-12-06 17:24:09下载
- 积分：1
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Euler_RungeKutta
四阶显示Runge-Kutta法绘制曲线(the matlab program of RK)
- 2011-12-15 14:52:37下载
- 积分：1
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QuadRotor_MA8.2
MB8四旋翼自动驾驶仪的源码，包括姿态采集，状态估计以及控制输出。不推荐直接使用，但是可以作为学习(MB8 four rotor autopilot source, including posture acquisition, state estimation and control output. Not recommended for direct use, but can be used as learning)
- 2014-01-15 16:52:27下载
- 积分：1
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turbine3
实现含风电场RX模型的系统潮流计算，风电场采用RX模型，此模型充分考虑风力发电机的输出功率特性，比其他模型完善，在模型中将迭代过程分为两步:常规潮流迭代计算和异步风力发电机的滑差迭代计算。( In short, the algorithm carried out to simulate the wind farmas an RX bus is as follows:
1)Begin with s=snorm in each machine, snorm being the rated slip of the same. With this value, calculate the impedance Z.
2)With these values, model the wind farm as an RX bus including the admittances of the machines in the admittance matrix and in the corresponding terms of the jacobian.
3)As a result of the first power flow, the voltages in the buses can be obtained. With these, can calculate the mechanical power of the machine.
4)With the value of s, calculate the power extracted the wind with .
5)Compare both powers and, if they are not equal, recalculate，by means of (G) and go to step 2. If they are equal, he algorithm finishes.)
- 2021-04-15 16:18:54下载
- 积分：1
