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matlab_saa3010
简介：采用matlab完成了SAAB3010红外遥控板的编码发射显示，通过GUI界面可以清楚了解其发射编码格式，有助于红外遥控编解码的学习。
关键词：matlab SAA3010 红外遥控 GUI(Description: The complete SAAB3010 matlab coding infrared remote control panel emission displays, through the GUI interface can be a clear understanding of its launch encoding, decoding infrared remote control help learning. Keywords: matlab SAA3010 Infrared Remote Control GUI)
- 2010-06-15 13:41:56下载
- 积分：1
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URLEncoding
自己写的URL编解码的工程基于vs2010，可以用于对法语，俄罗斯等语言进行编解码，主要在自己使用googlemap时使用(Write your own URL codec works based vs2010, can be used for French, Russian and other languages codec, mainly used in their own use googlemap)
- 2014-07-13 18:47:51下载
- 积分：1
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matlab[1]
介绍了一些简单的MATLAB用法和函数，适合初学者的学习。(Introduces some simple MATLAB usage and function, suitable for beginners to learn.)
- 2010-08-28 11:32:25下载
- 积分：1
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1011111111
matlab时频分析配套源码第11章的程序，请大家共享(Matlab time-frequency analysis supporting source Chapter 11 procedures, please share)
- 2007-04-11 18:54:35下载
- 积分：1
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singlepath
自己写的关于单径的MATLAB FADING信道仿真,很不容易写出来的 大家参考参考啊(himself wrote on the single-track MATLAB FADING channel simulation, very easy to write down all the information. ah)
- 2006-12-18 15:14:41下载
- 积分：1
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singlephase-uncontrolled-rectifier
含电容滤波的单相不可控整流电路的simulink仿真图(Capacitor filter containing a single-phase uncontrolled rectifier simulink simulation diagram)
- 2021-03-14 14:09:23下载
- 积分：1
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fdtd-code
光子晶体谐振腔的详细matlab编码，详细仿真了光在晶体谐振腔里的传播方式和特点。希望能从中领略编程的强大优势。
(photonic crystal resonant cavities)
- 2011-04-21 20:14:48下载
- 积分：1
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gafmax
％ [BestPop,Trace]=fmaxga(FUN,LB,UB,eranum,popsize,pcross,pmutation)
％ Finds a maximum of a function of several variables.
％ fmaxga solves problems of the form:
％ max F(X) subject to: LB <= X <= UB
％ BestPop--------最优的群体即为最优的染色体群
％ Trace----------最佳染色体所对应的目标函数值
％ FUN------------目标函数
％ LB-------------自变量下限
％ UB-------------自变量上限
％ eranum---------种群的代数,取100--1000(默认1000)
％ popsize--------每一代种群的规模；此可取50--100(默认50)
％ pcross---------交叉的概率,此概率一般取0.5--0.85之间较好(默认0.8)
％ pmutation------变异的概率,该概率一般取0.05-0.2左右较好(默认0.1)
％ options--------1×2矩阵,options(1)=0二进制编码(默认0),option(1)~=0十进制编码,option(2)设定求解精度(默认1e-4)( [BestPop, Trace] = fmaxga (FUN, LB, UB, eranum, popsize, pcross, pmutation) Finds a maximum of a function of several variables. Fmaxga solves problems of the form: max F (X) subject to : LB <= X <= UB BestPop-------- optimal chromosome groups is the best group Trace---------- chromosome corresponding to the best objective function value FUN------------ objective function LB------------- variable lower limit since the UB------------- variable upper limit eranum--------- populations algebra, take 100- 1000 (default 1000) popsize-------- population size of each generation this desirable 50- 100 (default 50) pcross--------- crossover probability, the probability of a general check 0.5- 0.85 between the better (default 0.8) pmutation------ mutation probability, the probability of 0.05 general admission better about-0.2 (default 0.1) options-------- 1 × 2 matrix, options (1) = 0 binary code (default 0), option (1) ~ = 0 decimal coding, option (2 ) set accuracy (default 1e-4))
- 2006-10-18 16:07:48下载
- 积分：1
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Stellaria-Demo-1.4.0
应用matlab，仿真雪花飘飞，非常的逼真直观(Application of Matlab simulation snowy, very realistic and intuitive)
- 2013-05-01 11:27:35下载
- 积分：1
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simulation
在一个移动通信系统中，发射信号是一个未调制的音频x(t)=cos(2πft)，其中f=f0+fi。设标称载波为f0=1GHz，并设fi =512Hz。假定移动用户在一个繁忙的高速公路上距离基站l公里处的地方，从开始从每小时60公里的速度开始，其速度（在0.01秒的时间间隔内测量）以1/2的概率随机的增加或减少1/10公里每小时。试仿真移动用户在这2s的时间间隔内所接收到的信号(及其频谱)。接收信号可以表示为：
y(t)=a(t)Cos[2π(fo+f1)(t-△t)]
式中 △(t)=d(t)/c
且 a(t)=k/d2(t)
在上面的表达式中d(t)是在t时刻基站与移动用户的距离，c是光速，△(t)是传播延迟，而a(t)是信号在t时刻的衰减，并假设在这2s内a(t)是一个常数。利用复低通等效模型来进行仿真。(In a mobile communication system, the transmitted signal is an unmodulated audio x (t) = cos (2πft), where f = f0+ fi. Let nominal carrier of f0 = 1GHz, and set fi = 512Hz. Assume that mobile users on a busy motorway station l kilometers place, starting the beginning of 60 kilometers per hour, the speed (measured in 0.01 second interval) to increase the probability of a random 1/2 or reducing 1/10 km/h. Simulation test signal which the mobile subscriber in the 2s time intervals of the received (and its spectrum). The received signal can be expressed as:
y (t) = a (t) Cos [2π (fo+ f1) (t- △ t)]
Where △ (t) = d (t)/c
And a (t) = k/d2 (t)
In the above expression, d (t) at time t is a base station and a mobile user s distance, c is the speed of light, △ (t) is the propagation delay, and a (t) is the attenuation of the signal at time t, and assuming that 2s within a (t) is a constant. Using complex low-pass equivalent model for emulation.)
- 2015-11-24 17:16:20下载
- 积分：1
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