-
VBLAST-simulation
本文对V-BLAST系统进行仿真,仿真比较采用干扰消除和无干扰消除的系统误帧率与SNR的关系曲线,并进行比较。(V-BLAST system simulation, simulation was used to compare the interference cancellation and without interference cancellation system, the frame error rate and SNR curve, and compare them.)
- 2012-07-05 10:37:14下载
- 积分:1
-
Digital-filtering-experiment
由设计要求可知,wp<=0.2π,允许误差幅度小于1dB,ws>=0.3π内衰减应大于15dB。为了验证数字滤波器的实际滤波功能,设计程序时,把输入序列定为验证函数x(t)=4sin(100πt)以及x(t)=4sin(200πt)和x(t)=4sin(400πt)。又因为Ts=1.25ms,T=80ms,故采样点为64,即N=64,所以当M=6,可以同时调试并验证程序的滤波功能。(Seen by the design requirements, wp < = 0.2π, allow a margin of error of less than 1dB, ws> = 0.3π within attenuation greater than 15dB. In order to verify the actual filtering function of the digital filter design program, the input sequence as validation function x (t) = 4sin (100πt) and x (t) = 4sin (200πt) and x (t) = 4sin (400πt) . And because Ts = 1.25ms, T = 80ms, so the sampling points is 64, that is N = 64, so when M = 6, can debug and validate filtering program.)
- 2014-12-24 09:34:43下载
- 积分:1
-
2209100144
controling speed of rotor
- 2012-10-18 19:56:03下载
- 积分:1
-
5
信号处理,进行信号检测与处理,通过设定threshold来进行信号检测的可信度调整(Credibility adjustment signal processing, signal detection and processing, by setting threshold for signal detection)
- 2013-12-02 04:20:06下载
- 积分:1
-
flysimulation
基于空间飞行器的姿态仿真源程序,仿真表明非常的准确。(Based on the spacecraft attitude simulation source code, simulation shows that very accurate.)
- 2007-12-11 18:19:13下载
- 积分:1
-
rotation
image rotation,for rotating skewed images of document images
- 2010-12-22 14:06:01下载
- 积分:1
-
ACOtsp
this file consists files witch can use aco for tsp
- 2011-07-29 21:02:41下载
- 积分:1
-
Matlab-function-for-image-processing
matlab图像处理函数大全,希望对初学者有一定帮助。(matlab image processing function Daquan, hope there is some help for beginners.)
- 2013-01-22 20:46:08下载
- 积分:1
-
KFalphabeta
kalman滤波算法与alpha-beta滤波算法的比较,通过比较,验证两种算法各自的优缺点。(Comparison, Kalman filtering algorithm and alpha-beta filtering algorithm by comparing the advantages and disadvantages of verification, two algorithms.
)
- 2014-06-17 14:59:10下载
- 积分:1
-
ForK1
我们的目的是将一个分数拆分成若干个分子是1分母是正整数的分数之和的形式。例如2/3可以拆分成1/2+1/6的形式。这里不考虑顺序,比如1/6+1/2和1/2+1/6相同。
输入p, q, a, n, 其中p/q为分数,对这个分数进行拆分,要求拆分的分数个数不能多于n个,所有分母的乘积不能大于a。求有多少种拆分方法?
输入:最多200组数据。在每行中都有四个数分别表示p, q, a, n,之间以空格隔开,并且满足p,q<=800,a<=12000,n<=7,最后以四个0做为输入的结束。
输入示例:
2 3 120 3
2 3 300 3
0 0 0 0
输出示例:
4
7
(Our aim is to split a fraction into a number of elements is a denominator is a positive integer fraction of the sum of form. For example, 2/3 can be split into 1/2+1/6 form. Not considered here, the order, such as 1/6+1/2 and 1/2+1/6 of the same. Input p, q, a, n, where p/q as a fraction of this split scores require no more than the number of split points n-all the product of the denominator can not be larger than a. How many kinds of demand split method? Input: Up to 200 sets of data. In each line has four numbers indicate the p, q, a, n, separated by a space between, and meet the p, q < = 800, a < = 12000, n < = 7, the end, four 0 as the input end. Input Example: 2,312,032,330,030,000 sample output: 47)
- 2009-11-12 09:54:17下载
- 积分:1