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face
对人脸的角度进行识别，主要作用于两眼之间的距离(The perspective of human face recognition, a major role in the distance between the eyes)
- 2010-05-10 13:38:10下载
- 积分：1
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matlab--zigzag
用matlab实现zigzag扫描，H.264帧内编码中不可缺少的环节(Zigzag scan using matlab implementation, H.264 intra-coded indispensable part in the)
- 2011-05-09 18:43:58下载
- 积分：1
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Impact-Cost
上传的matlab程序是股票市场的市场冲击成本程序，欢迎大家下载查阅！(the file is the matlab program of Impact Cost! )
- 2013-09-26 08:57:21下载
- 积分：1
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DOA4
面阵中二维角度估计 Unitary -ESPRIT算法MATLAB程序(Two-dimensional planar array angle estimation algorithm based on MATLAB program Unitary-ESPRIT)
- 2015-04-14 18:13:41下载
- 积分：1
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Pack Kurtogram V4
说明： kurtogram是一种四阶谱分析工具，用于检测和表征信号中的非平稳性。可用于轴承的故障诊断(The kurtogram is a fourth-order spectral analysis tool elaborated for detecting and characterising nonstationarities in a signal. It relies on the assertion that each type of transient is associated with an optimal (frequency/frequency resolution) dyad (f ; Df) which maximises the kurtosis. The Fast Kurtogram computes the kurtogram over a grid that finely samples the (f ; Df) plane. Its complexity is on the order of N log N.
This is the "plain vanilla" code used in paper:
J. Antoni, Fast Computation of the Kurtogram for the Detection of Transient Faults, Mechanical Systems and Signal Processing, Volume 21, Issue 1, January 2007, Pages 108-124.)
- 2020-10-30 22:20:01下载
- 积分：1
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212
说明： matlab实例编程一百个源程序matlab实例编程一百个源程序(matlab matlab source code examples of programming one hundred one hundred instances of programming source code)
- 2010-03-31 19:15:54下载
- 积分：1
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Porous_Medium_Flows
多孔介质内流动的格子Boltzmann方法源代码(lattice boltzmann method to simulate fluid flow in porous medium.)
- 2011-06-14 17:06:37下载
- 积分：1
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twopointp
说明： 解两点边值问题的有限元程序代码（matlab）(Solution of Boundary Value Problems of Finite Element code (matlab))
- 2010-04-07 15:55:22下载
- 积分：1
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传递熵Matlab
这个只是一个计算马尔科夫系统传递熵的matlab，函数希望大家能把他用到高维中，并分享(This is just a calculation of Markov system transfer entropy MATLAB, function, I hope we can use it to high dimension, and share)
- 2017-08-08 14:38:21下载
- 积分：1
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lab3
lear
N = 10^5
EB_NO = [-1:30]
liu1 = zeros(1,N)
liu2 = zeros(1,N)
for ii = 1:length(EB_NO)
m= (2*(rand(1,N)>0.5)-1) + j*(2*(rand(1,N)>0.5)-1)
s = (1/sqrt(2))*m normalization of energy to 1
n = 1/sqrt(2)*[randn(1,N) + j*randn(1,N)]
- 2012-05-17 19:57:23下载
- 积分：1
