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ss_Pe97
说明： 此代码描述的是跳频系统在不采用两路分集的情况下的性能仿真，主要也是对误码率的仿真函数(This code describes the frequency-hopping system without two-way diversity in cases where performance simulation, is largely a function of the BER simulation)
- 2010-03-29 22:02:12下载
- 积分：1
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imagefusion
用wavedec2()函数对b1,b2两幅图像进行小波分解, 采用’db1’小波,分解到第三级 融合两幅图像。(With wavedec2 () function b1, b2 the two images were decomposed using ' db1' wavelet decomposition to the third level fusion of two images.)
- 2010-05-10 20:42:37下载
- 积分：1
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hosademo
这是hosa工具箱中使用各种函数的一些例子或原始数据，对于指导如何使用hosa工具箱中的函数很有帮助。(this is the demo of the matlab toolbox hosa. it s helpful to teach you how to use the functions of hosa toolbox.)
- 2009-05-31 22:21:38下载
- 积分：1
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Solutiontosomemathsalgorithmusingmatlab
本代码详细说明了在matlab中,如何求解各种数学中的算法问题,方便了科研人员的使用.(Detailed description of the code in matlab, how to solve mathematical problems in the algorithm and make it easier for researchers to use.)
- 2007-07-31 13:11:35下载
- 积分：1
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get_hist_google_stock_data
MATLAB连接GOOGLE数据库的例程,Script to Retrieve Historical Stock Data from Google Finance(Script to Retrieve Historical Stock Data from Google Finance)
- 2013-02-02 09:06:19下载
- 积分：1
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Frequency-Response-Plotter-Code_matlab
Once you input filter coeffiecient you can get frequency responce of filter and drawing that shows the position of pole, zero.
- 2012-07-29 15:24:42下载
- 积分：1
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GPIO-V2
Core M3直接操作寄存器控制GPIO的用法。(Core M3 directly manipulate registers control the GPIO usage.)
- 2013-11-28 09:54:33下载
- 积分：1
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分洪问题
工件加工问题，本程序提供了工件加工问题的一般算法question1 question2 question3经过调试能成功运行(workpiece machining, the process of machining the general algorithm question1 question2 question3 after the successful operation Debugging)
- 2005-08-27 16:08:18下载
- 积分：1
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advancenewton
说明：
改进的牛顿法求解：
方程的构造方法:给出[0,1]区间上的随机数(服从均匀分布)作为方程的根p*.
设你的班级数为a3,学号的后两位数分别为a2与a1,从而得到你的三次方程
例如:你的31班的12号,则你的方程是21x3+60x2+2x+a0=0的形式.
方程中的系数a0由你得到的根p*来确定.
(improve Newton's method : Construction of the equation : given interval [0,1] on the random number (subject to uniform distribution) as the root equation p*. set up your classes at a3, after learning of the double-digit for a1 and a2, so you get the three equations for example : Your 31 classes on the 12th, then your equation is 21x3 60x2 2x a0 = 0 forms. the equation coefficients a0 you get from the root of p* to determine.)
- 2005-12-03 18:16:08下载
- 积分：1
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waveform_design
雷达中线性调频信号的脉冲压缩，距离普，多普勒谱及其回波仿真(Chirp radar signal pulse compression, the distance P, and echo Doppler spectrum simulation)
- 2014-02-27 15:43:26下载
- 积分：1
