登录
首页 » matlab » unit-commitmentdynamic

unit-commitmentdynamic

于 2015-04-10 发布 文件大小:1KB
0 22
下载积分: 1 下载次数: 11

代码说明:

  code for unit commitment problem power system analysis

下载说明:请别用迅雷下载,失败请重下,重下不扣分!

发表评论

0 个回复

  • poik
    matlb qpsk code used in chnest
    2010-05-06 17:50:25下载
    积分:1
  • rate_1_N_convolution_code
    matlab仿真,有关纠错码中卷积码的性能仿真,1/N速率的(matlab simulation, the error-correcting codes in the convolutional code performance simulation, 1/N rate)
    2010-12-03 22:31:09下载
    积分:1
  • Homing_GuDingTiQianJiao
    说明:  固定提前角法跟踪的数学模型及其仿真程序代码。(A fixed angle in advance of the mathematical model for tracking and simulation code.)
    2009-08-17 19:27:35下载
    积分:1
  • Optimization-of-fuzzy-control
    Optimization of a gas turbine engine fuzzy control
    2013-11-13 15:07:36下载
    积分:1
  • ORGANISER-LE
    program simulink about mimo system
    2012-02-07 19:54:04下载
    积分:1
  • slamSimulation
    slam simulation for robot cartoggraphy and mapping with out external sensors
    2014-01-12 00:38:08下载
    积分:1
  • Filter
    使用EKF、UKF、PF、EKPF算法实现简单的单个目标跟踪滤波(Using EKF, UKF, PF, EKPF simple tracking algorithm filter)
    2021-03-05 15:49:31下载
    积分:1
  • DCT_IDCT
    to understand the Algorithm go to matlab help in page dct2 and idct2 to get the mathematical expression for M = N = 8, we can calculate the most of hard values and save it as LUTs to speed up the execution now compare our special 8X8 functions with the internal general functions use this code: A = int32(100*rand(8,8)) tic for i = 1 : 1000 IDCT_8X8(DCT_8X8(A)) end toc tic for i = 1 : 1000 idct2(dct2(A)) end toc i had built the general functions too, but with low speed (to understand the Algorithm go to matlab help in page dct2 and idct2 to get the mathematical expressionfor M = N = 8, we can calculate the most of hard values and save it as LUTs to speed up the executionnow compare our special 8X8 functions with the internal general functionsuse this code: A = int32 (100* rand (8,8)) tic for i = 1: 1000 IDCT_8X8 (DCT_8X8 (A)) end toc tic for i = 1: 1000 idct2 (dct2 (A)) end toc i had built the general functions too, but with low speed)
    2007-12-05 18:28:42下载
    积分:1
  • yuanma
    说明:  求解方程-u"(x)+u(x)=exp(x)*(sin(x)-2*cos(x))两点边值问题(Solve the equation-u &quot (x)+ u (x) = exp (x)* (sin (x)-2* cos (x)) Boundary Value Problems)
    2010-04-30 09:13:41下载
    积分:1
  • Centroid
    质心定位算法源码,分三种情况考虑,只有锚节点,被定位到的未知节点也作为锚节点,有邻居锚节点的未知节点只利用邻居锚节点进行定位,没有邻居锚节点的未知节点才利用已经定位了的邻居未知节点进行定位。 (Centroid localization algorithm source,Three cases to consider.Only the anchor nodes,unknown nodes to be positioned as anchor nodes,neighbor anchor node of the unknown node using only neighbor anchor node positioning, not unknown neighbor anchor node node neighbor has positioned the unknown node positioning.)
    2013-03-21 20:05:47下载
    积分:1
  • 526605资源总数
  • 44211会员总数
  • 348今日下载