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bfs
这是BFS算法的实现。用C语言实现的。好好学习吧。(This is achieved BFS algorithm. Implemented using C language. Learn it.)
- 2013-12-05 15:56:50下载
- 积分：1
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Dijlstra
Dijlstra算法 对任意图，选择合适的数据结构表示图，在此基础上实现求解最短路径的Dijkstra算法(Dijlstra algorithm to arbitrary map, select the appropriate data structures that map, on this basis to achieve solution of the Dijkstra shortest path algorithm)
- 2009-01-11 19:03:11下载
- 积分：1
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qiongju
八皇后算法，用的是最简单的穷举法，在VC++6.0上编写的。(Eight Queens algorithm, using the simplest method of exhaustion, in VC++6.0 written on.)
- 2013-08-14 22:21:28下载
- 积分：1
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Circlist_Josephus3_4
循环链表的应用
循环链表的应用
很方便的实现(cycle Chain cyclic chain of convenience Implementation)
- 2006-11-23 19:36:47下载
- 积分：1
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binary
实现对二叉树的操作：建树、遍历、求层高、叶子数和结点数等(binary tree)
- 2011-12-09 15:58:29下载
- 积分：1
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Figure-topological-sort
说明： 拓扑排序
对一个 有向无环图 G进行拓扑排序，是将G中所有顶点排成一个线性序列，使得图中任
意一对顶点u和v，若u，v ∈E，则u在线性序列中出现在v之前。
通常，这样的线性序列称为满足拓扑次序的序列，简称 拓扑序列 。
注意：
①若将图中顶点按拓扑次序排成一行，则图中所有的有向边均是从左指向右的。
②若图中存在有向环，则不可能使顶点满足拓扑次序。
③一个DAG的拓扑序列通常表示某种方案切实可行。 (Topological sort
In a directed acyclic graph G topological sort, is all vertices will G formed a linear sequence, make diagram post
Meaning a pair of vertex u and v, if u, v ∈ E, then u in linear sequence in which they appear in v before.
Usually, such linear sequence sequence of topological order called meet, abbreviation topology sequence.
Note:
(1) if the diagram according to the topology order line vertices, then figure all from left to right edge are pointing.
(2) if the figure to exist in the ring, is impossible to have the vertex meet topological sequence.
(3) a DAG topological sequence usually expressed some scheme is feasible.
)
- 2011-03-22 17:19:14下载
- 积分：1
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123
校园导航系统
1） 校园景点介：绍介相关景点的有关详细信息。
2） 最佳路线查询：查询校园中任意两点之间所有路线，并提供两点间最短的简单路径。
3） 关节点查询：提供校园图的关节点查询。
4） 多景点最佳路线查询：提供多个景点的最佳线路查询，即求途径这个景点的最佳路径。
(Campus Navigation System 1) campus attractions Introduction: Shao Jie-related attractions for more information. 2) The best route query: Query on campus all the routes between any two points, and provides a simple shortest path between two points. 3) joint points: the key points to provide the campus map queries. 4) The best route queries more attractions: multiple sites to provide the best route queries, that is seeking ways to this spot the best path.)
- 2011-08-25 08:56:05下载
- 积分：1
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Task1-trial--10211281--zly
描述：足球俱乐部包括球员、普通行政人员。球员有姓名、年龄、能力、年薪、转会费、进球总数、服役年限等重要参数；普通行政人员有姓名、年龄、能力、年薪等参数。你需要给相关管理机构开发一个管理程序，实现对众多足球俱乐部管理的基本功能。具体功能包括：
a) 俱乐部的增删改查，俱乐部的属性包括名称、现金、其下人员；
b) 可以对所有球员的各项属性进行简单搜索，支持输入多个条件，条件之间用&&连接，例如：
i. “年龄不大于25且服役年限大于5年且进球数大于100的球员”，查询表达式：!(@age>25) && @experience>5 && @kick>100
c) 支持球员在不同俱乐部间的买卖，买卖需符合以下条件：作为买方的俱乐部的现金>=球员的转会费，交易完成后，卖方将得到转会费。
要求：
d) 必须采用面向对象的方式，使用类组织数据结构，并注意类的继承关系；
e) 在题目要求基础上可以自行扩展功能，提供扩实用扩展功能者适当加分（加分不超过5分）。
(Description: Football club including players, general administrative staff. Player name, age, ability, salary, transfer fee, total number of goals, service life and other important parameters ordinary administrative staff name, age, ability, salary and other parameters. You need to give the relevant management agencies to develop a management program to achieve the number of football club management s basic functions. Specific features include:
a) the club CRUD, the name of the club s property, including cash, under which personnel
b) all players can perform a simple search of the property, supports input multiple conditions with && connection between conditions, for example:
i. "Age is not greater than 25 and greater than 5 years service life and goals more than 100 players," query expression:! (@ age> 25) && @ experience> 5 && @ kick> 100
c) Support the players traded between different clubs, the sale subject to the following conditions: As a buyer s club cash> = pl)
- 2013-08-20 10:09:29下载
- 积分：1
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class
给定m个n维向量a , a , ,am 1 2 ，向量分类问题要求将相同的向量划分为同一类。试用
抽象数据类型表设计解向量分类问题的有效算法。(Given m a n-dimensional vector a, a,, am 1 2 )
- 2008-05-05 22:03:41下载
- 积分：1
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hellow4
序列二次规划算法，能求解包含约束和无约束的问题，非常方便。(Sequential quadratic programming algorithm to solve constrained and unconstrained contain the problem, very convenient.)
- 2021-01-08 18:18:51下载
- 积分：1
