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fsk
this project is about phase shift keying
- 2013-01-04 18:20:51下载
- 积分：1
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echant_fft
sampling of some signal and fft representation
- 2011-01-13 11:05:09下载
- 积分：1
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processing-time--signals-
matlab时域信号处理算例，包括带通滤波、高通滤波、低通滤波(signals processing in time domain ,including Low pass filter
,high pass filter，Band pass filter)
- 2012-04-05 13:46:02下载
- 积分：1
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shiyanerdaima
通过电子Smith圆图实现L型阻抗匹配，分析L型阻抗匹配网络的匹配种类和计算L、C的值。(L impedance matching was achieved through electronic Smith chart, analysis of l-shaped impedance matching network of matching types and calculating the value of L, C.
)
- 2013-05-04 22:26:30下载
- 积分：1
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ofdm
matlab实现的OFDM仿真程序，及详细的说明文档(matlab implementation of OFDM simulation program, and detailed documentation)
- 2015-04-13 16:26:43下载
- 积分：1
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particleFilterTrackTest
通过粒子滤波来跟踪目标 可以在vs2008下直接运行(Through the particle filter to track the targets can be run directly under vs2008)
- 2010-06-22 20:57:07下载
- 积分：1
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m32test
小m序列生成程序，可以生成32比特长度的小m序列并具有相对好的自相关特性(m sequence generate)
- 2010-06-24 19:56:07下载
- 积分：1
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yuyinjiequ
用于截取较长的语音文件，生成新的文件，方便使用，(For the interception of a long sound files, generates a new file, easy to use,)
- 2010-02-01 15:43:18下载
- 积分：1
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92a99a1dc832fc8f6eb04971e20c455b
说明： 基于模糊PID的温度控制系统,通过matlab平台对基于模糊PID的温度控制系统进行设计(PID temperature controller design based on fuzzy control: fuzzy control and PID control combine to achieve PID adaptive approach to control system temperature by means of fuzzy control. This Fuzzy- PID strategy is not to replace the use of fuzzy control PID control, but the traditional control methods to improve and expand, both to maintain a simple and conventional PID control system structure, easy to use, robust, and high control accuracy advantages, but also the use of fuzzy inference PID parameters to achieve the PK, IK, DK-line self-tuning, both the fuzzy control flexibility, adaptability features, compared to simply have a good control effect either)
- 2020-04-06 21:18:49下载
- 积分：1
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0
说明： 给定n种物品和一个背包,物品i的重量是Wi,价值是vi,被包容量是C,应该如何选择装入被包的物品,使得装入背包中物品的总价值最大?对于每种物品i,只有两种选择,装入或者不装入.
输入:第一行两个正整数n(物品数)和C(容量)
第二行n个正整数n,表示物品价值
第三行n个正整数n,表示物品重量
输出:第一行表示总价值
第二行n个数(0/1),0表示物品不装入,1表示装入
例如,
输入:
5 10
6 3 5 4 6
2 2 6 5 4
输出
15
1 1 0 0 1
(Species of a given n items and a backpack, the weight of item i is Wi, the value of vi, was packet capacity is C, should be how to choose a package of items to be loaded, the backpack load in the largest total value of goods? For each item i, there are only two options, loaded or not loaded. Input: the first line of the two positive integer n (the number of items) and C (capacity) of the second line of n positive integer n, that the value of the third line of n positive integer n, that the weight of output: the total value of the first line of the second line, said n number of (0/1), 0 that the items do not load, that load 1 for example, enter: 5,106,354,622 6 5 4 output 15 1 1 0 0 1)
- 2009-07-01 23:07:01下载
- 积分：1
