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image_proccessing_1
image processing procedures
- 2010-12-15 06:19:43下载
- 积分：1
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cgls
共轭梯度方法求解正定方程。该种解法有效的处理了正定方程的求解速度问题。CGLS Conjugate gradient algorithm applied implicitly to the normal equations.(CGLS Conjugate gradient algorithm applied implicitly to the normal equations.)
- 2011-09-09 00:43:29下载
- 积分：1
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boost
dc/dc boost converter
- 2013-02-09 07:29:25下载
- 积分：1
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one1
一个matlab gui小代码，用于数据进制的转换(A small code matlab gui for data hex conversion)
- 2013-08-23 10:13:02下载
- 积分：1
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main_test1
利用FSWT对信号进行分析，实现故障信号的分离与提取，用于检测机械设备的故障诊断(Fault diagnosis)
- 2021-04-22 09:28:49下载
- 积分：1
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xinhaokechengsheji
我们数字信号处理课程设计的所有内容的最终版本内附总结(We design digital signal processing course the final version containing all the content summary)
- 2010-06-13 22:24:25下载
- 积分：1
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shibie
matlab图像处理，matlab图形识别匹配应用程序源码(matlab image processing, matlab matching pattern recognition application source code)
- 2013-12-03 19:40:34下载
- 积分：1
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AIC
AIC信息准则法的系统辨识程序，通过系统输入输出辨识出系统的传递函数。(system identification program of AIC Information Criterion method:identified by the system input-output transfer function of the system.)
- 2015-09-18 21:50:49下载
- 积分：1
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pi_method1
Estimated number of Pi ( Method 1)
how do we estimate Pi by simulation? In the simulation, you keep throwing darts at random onto the dartboard. All of the darts fall within the square, but not all of them fall within the circle. Here s the key. If you throw darts completely at random, this experiment estimate the ratio of the area of the circle to the area of the square, by counting the number of darts in each.
Our study of the geometry tells us this ratio is Pi/4. So, now we can estimate Pi as
- 2013-04-29 02:49:47下载
- 积分：1
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filter
M=63 J=(M-1)/2 Wp=0.5*pi Ws=0.6*pi
Np=100 Ns=100
weightp=1 weights=100 通带和阻带的加权系数
WpN=linspace(0,Wp,Np)
WsN=linspace(Ws,pi-0.05,Ns)
Wm=[WpN WsN]
p=[ones(1,50),ones(1,50)/2]
d=[p,zeros(1,Ns)]
W=diag([weightp*ones(1,Np),weights*ones(1,Ns)])
C=cos(Wm*[0:J])
Q=diag(cos(Wm*0.5))
g=(W*Q*C)(W*d) g=g
h=(g(J:-1:2)+g(J+1:-1:3))/4
h=[g(J+1)/4 h g(1)*0.5+g(2)/4]
h=[h fliplr(h)] W=linspace(0,pi-0.1,512)
H=freqz(h,1,W)
plot(W/pi,20*log10(abs(H)))
(filter design)
- 2013-05-18 20:47:33下载
- 积分：1
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