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One-dimensional-extremum-problem
说明: 第6章 无约束一维极值问题
所在章节 函数名 功 能
6.1 minJT 用进退法求解一维函数的极值区间
6.2 minHJ 用黄金分割法求解一维函数的极值
6.3 minFBNQ 用斐波那契法求解一维函数的极值
6.4 minNewton 用牛顿法求解一维函数的极值
6.5 minGX 用割线法求解一维函数的极值
6.6 minPWX 用抛物线法求解一维函数的极值
6.7 minTri 用三次插值法求解一维函数的极值
6.8.1 minGS 用Goldstein法求解一维函数的极值
6.8.2 minWP 用Wolfe-Powell法求解一维函数的极值
(Chapter 6 unconstrained extremum problem one-dimensional sections of the functional 6.1 minJT function method for solving one-dimensional with the advance and retreat of the extreme range of 6.2 minHJ function of the golden section method using one-dimensional function of the extreme 6.3 minFBNQ use Fibonacci method one-dimensional function of the extreme 6.4 minNewton Newton method with one-dimensional function with extreme 6.5 minGX one-dimensional secant method to solve the extreme 6.6 minPWX function method for solving one-dimensional parabolic function of the extreme 6.7 minTri method with cubic interpolation one-dimensional function of the extreme 6.8.1 minGS Goldstein method with one-dimensional function of the extreme 6.8.2 minWP Wolfe-Powell method with a one-dimensional extreme value function)
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- 积分:1
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Matlab-senior-notes
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Bessel
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jacenc
JPEG AC coefficient encoding routine
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speech-test
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1.to find the euclidian distance
2.to create mel frequency filter bank
3.
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Motion-PeopleDetection
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design
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tiaosu
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