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hamidunp2Boulatu
关于中国邮递员的解决办法，个人觉得还不错的说(Chinese postman)
- 2012-06-10 17:28:15下载
- 积分：1
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哈夫曼树解码和编码
哈夫曼树，基本的数据结构，用来编码和解码、用数组作为存储结构实现，
- 2023-04-13 11:00:11下载
- 积分：1
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data-structure-paper
本资料为数据结构的相关试卷，可以帮助大家解决一下有关考试的问题(This information is relevant papers data structure that can help you solve the problems concerning the examination)
- 2013-09-18 08:16:24下载
- 积分：1
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yuesehuhuan
就是一个简单的约瑟夫环实现程序。主要就是在痛过程序实现栈的实现。(Joseph is a simple procedure to achieve ring. The main program is in pain over the realization of the realization of the stack.)
- 2007-11-22 11:35:10下载
- 积分：1
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maopao_youhua
冒泡优化：
如果一个序列是int n[]={1,2,3,4,5,6,7,8,9} , 用正常的冒泡排序需要排8次才行，优化之后1次就好，也就是说序列越接近于正常序列，改进之后的冒泡排序的次数就越少，这样会给一个冒泡排序算法带了很大的效率。
思想：添加一个boolean变量用来判断冒泡是否是已经排好了顺序，如果boolean的值为false，说明是已经排好了，如果boolean的值true，说明没有排好，继续排。(If a sequence is int n [] = {, 1,2,3,4,5,6,7,8,9} need to row 8 times the job after optimization times like normal bubble sort, but alsomeans that the sequence is more close to the normal sequence, improved bubble sort, the less the number, which would give a bubble sort algorithm with a great deal of efficiency.
Idea: add a boolean variable used to determine the bubble whether it is already lined up the order, if the boolean is false, indicating already lined up, if the boolean value of true, did not line up, continue to row.)
- 2012-04-18 00:33:45下载
- 积分：1
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LStack
堆栈实现C++,以VC++环境为准——逍遥大洋至上(The stack of the C++, VC++ environment will prevail)
- 2012-03-26 08:35:26下载
- 积分：1
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LR(0)
简单LR语法分析程序自动生成器的实现，可用作数据结构课程设计(LR (0) grammar analysis)
- 2013-09-22 09:26:25下载
- 积分：1
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CAR
some problems about c++.(car.cpp)
- 2012-01-12 14:39:48下载
- 积分：1
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hellow4
序列二次规划算法，能求解包含约束和无约束的问题，非常方便。(Sequential quadratic programming algorithm to solve constrained and unconstrained contain the problem, very convenient.)
- 2021-01-08 18:18:51下载
- 积分：1
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astar
A*算法 1、将开始节点放入开放列表(开始节点的F和G值都视为0)
2、重复以下步骤:
在开放列表中查找具有最小F值的节点,并把查找到的节点作为当前节点
把当前节点从开放列表删除, 加入到封闭列表.
(A* algorithm 1, will begin to node placed in the and opening up list of (the began to node of the F and G values are regarded as 0) 2, repeat the the following steps: to Find a the has a the the smallest F value of the node in the the and opening up list of, and put Find a to the node as the current node current node is removed from the open list, added to the closed list.)
- 2013-04-04 11:06:42下载
- 积分：1
