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copula

于 2021-04-07 发布文件大小:67KB

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下载积分: 1 下载次数: 23

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代码说明：

GOOGLE代码网站最全的COPULA公式MATLAB合集(COPULA formula code on GOOGLE website the most complete collection for MATLAB)

文件列表：

copula
......\alphaboundaries.m,541,2007-06-21
......\analytic
......\analytic.mws,33666,2007-02-13
......\bcs.m,2902,2007-02-13
......\check_alpha.m,2618,2006-11-24
......\check_tau.m,2687,2006-11-24
......\conditionalcdf.m,2311,2006-11-24
......\constrain_tau.m,721,2006-11-24
......\copulacdf.m,3826,2006-12-11
......\copulaparam.m,2513,2006-12-11
......\copulapdf.m,8337,2007-06-21
......\copularnd.m,3817,2007-06-21
......\copulastat.m,1866,2007-06-21
......\dilog.m,1733,2006-11-09
......\isnear.m,1055,2006-11-10
......\kendall.m,1241,2006-12-11
......\lambdaarch.m,9171,2007-06-21
......\posterior.m,1141,2007-06-21
......\quadg.m,7630,2007-06-21
......\README.txt,1821,2007-06-21
......\tauboundaries.m,1048,2007-06-21
......\taujacobian.m,1862,2007-06-21
......\tests
......\.....\discharge.txt,680,2006-11-14
......\.....\example.m,1226,2006-11-24
......\.....\tau_jacobian2.m,76,2006-12-11
......\.....\TestSuite.m,1005,2006-12-11
......\.....\test_bcs.m,1441,2007-02-13
......\.....\test_check_alpha.m,603,2006-12-11
......\.....\test_check_tau.m,490,2006-12-11
......\.....\test_copulacdf.m,1383,2006-12-11
......\.....\test_copulaparam.m,598,2006-12-11
......\.....\test_copulapdf.m,2885,2006-12-11
......\.....\test_copularnd.m,698,2007-02-13
......\.....\test_copularnd2.m,734,2006-12-11
......\.....\test_copulastat.m,2124,2006-12-11
......\.....\test_posterior.m,1162,2006-12-11
......\.....\test_taujacobian.m,1821,2006-12-11
......\.....\volume.txt,680,2006-11-10

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利用非线性控制完成光伏并网逆变器的设计，设计中采用先进的反步法，介绍很好。(Using nonlinear control to complete the design of the photovoltaic (pv) grid inverter, adopted in the design of advanced reverse moves, the introduction is very good.)

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VP8 Data Format and Decoding Specification

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Simple Contact Information System

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积分：1
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第k小元素（分治法）给定一个线性序列集，要求求出其中指定的第K小的数的值和位置.如给定n个元素和一个整数i，1≤i≤n，输出这n个元素中第i小元素的值及其位置；(First k small element (divide and conquer) Given a set of linear sequence, where the specified requirements determined the K value and the small number of locations, such as a given n elements and an integer i, 1 ≤ i ≤ n, output this is the n elements of the i-th element value and the position of the small )

2013-11-16 11:51:31下载

积分：1
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积分：1

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