登录
首页 » matlab » 地震响应

地震响应

于 2017-07-02 发布 文件大小:1056KB
0 209
下载积分: 1 下载次数: 14

代码说明:

  将所提供的28条地震动的加速度幅值调整为0.2g,计算并绘制相应的平均加速度反应谱(阻尼比为5%),并以该反应谱为基础,采用振型分解反应谱法计算各楼层的地震力。(The seismic force of each floor is calculated by the mode decomposition response spectrum method.)

文件列表:

地震响应
地震响应\code.m
地震响应\E_Displacement.m
地震响应\Ground_Motions_Suites123.rar

下载说明:请别用迅雷下载,失败请重下,重下不扣分!

发表评论

0 个回复

  • FMC 接口标准ANSIVITA_57.1.pdf
    FMC的接口标准,设计选择参考选型。国际标准所使用FMC 接口标准ANSIVITA_57。(FMC interface standards, design selection, reference selection. The international standard uses the FMC interface standard ANSIVITA_57)
    2017-07-20 10:30:09下载
    积分:1
  • 测试用例模板
    为测试人员提供便捷的软件测试用例模板,挺好的资料(Provide a handy template for testing software for testers, which is good information)
    2017-07-14 17:42:11下载
    积分:1
  • KTV(diangeyuandaima)
    KTV点歌程序的源代码,包含readme文件。(The song source code。Including the document of readme. )
    2012-01-07 18:34:16下载
    积分:1
  • 学生成绩核算系统的设计与实现(25) 要求:(1)按班级按课程从文件中读入相应的平时成绩、期中考试成绩和期末考试成绩。 (2)三个成绩对总评成绩的百...
    学生成绩核算系统的设计与实现(25) 要求:(1)按班级按课程从文件中读入相应的平时成绩、期中考试成绩和期末考试成绩。 (2)三个成绩对总评成绩的百分比被定义为常数,各占总成绩的30 、30 和40 。 (3)计算每位学生的总评成绩。 (4)计算该班级本课程的总平均成绩。 (5)计算处于优、良、中、及格、不及格的学生人数以及占总人数的百分比。其中100-90为优,89-80为良,79-70为中,69-60为及格,60分以下为不及格。 (6)按要求输出成绩在优、良、中、及格、不及格各区间的学生学号、成绩。-The student achievement calculation system s design with realizes (25) Request: (1) reads in the corresponding usual result, the midterm examination result and the terminal examinations result according to the class and grade according to the curriculum from the document. (2) three result are defined to the general appraisal result s percentage as the constant, occupies the overall result respectively 30 , 30 and 40 . (3) calculates each student s general appraisal result. (4) calculates this class and grade this curriculum the population mean result. (5) calculates the student population which is in superiorly, good, passes an examination, does not pass an examination as well as accounts for the total number of peop
    2022-03-15 21:39:52下载
    积分:1
  • 地图 服务 人物 开启程式补充 纯属开启
    地图 服务 人物 开启程式补充 纯属开启-Map Service figures to open the program to add a purely open
    2022-04-19 03:10:12下载
    积分:1
  • Pocket 1945 is a classic shooter inspired by the classic 1942 game. The game is...
    Pocket 1945 is a classic shooter inspired by the classic 1942 game. The game is written in C# targeting the .NET Compact Framework. This article is my first submission to Code Project and is my contribution to ongoing .NET CF competition.
    2022-05-08 20:43:25下载
    积分:1
  • power_brushlessDCmotor22
    matlab 直流无刷电机仿真,通过PI 控制器控制电机的转速恒定。(Matlab DC brushless motor simulation, through the PI controller to control the motor speed constant.)
    2018-06-21 17:28:52下载
    积分:1
  • C++语言实现阶乘,这是一种简单的实现方法,值得借鉴
    C++语言实现阶乘,这是一种简单的实现方法,值得借鉴-factorial C language, this is a simple method, worth learning
    2022-02-01 13:15:31下载
    积分:1
  • PSO
    说明:  带有约束的粒子群算法,求自己需要的极大值极小值。(Particle swarm optimization with constraints)
    2020-05-07 20:00:10下载
    积分:1
  • java_cmpp2.0-master
    说明:  通信双方以客户-服务器方式建立TCP连接,用于双方信息的相互提交。当信道上没有数据传输时,通信双方应每隔时间C发送链路检测包以维持此连接,当链路检测包发出超过时间T后未收到响应,应立即再发送链路检测包,再连续发送N-1次后仍未得到响应则断开此连接。(Both sides of communication establish TCP connection in client-server mode for mutual submission of information. When there is no data transmission on the channel, both sides of the communication should send link detection packages every other time C to maintain this connection. If the link detection packages do not receive a response after sending out more than time T, the link detection packages should be sent immediately, and then the link detection packages should be disconnected if they have not received a response after sending N-1 consecutive times.)
    2020-06-19 03:00:01下载
    积分:1
  • 696516资源总数
  • 106562会员总数
  • 4今日下载