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convolution
稀疏脉冲反褶积代码,包括高尔消元法解矩阵方程阻,自相关,互相关,褶积,反褶积的代码.
刚参加工作那会儿,上进心也足,爱动脑,编了很多的程序,唯有这一个是我引以为傲的,花了几个星期写的稀疏脉冲(预测)反褶积的代码,放到了现在,觉得也没必要再私藏下去了,不出五年,我都不知道这段代码是干什么的了.
希望对大家有用,方法太简单,所以效果不是太好,请大家修改,如要转载,请记得注明出处.
(vc++)
- 2009-05-09 16:51:58下载
- 积分:1
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RollingForceCal
计算热轧中的单机架的轧制压力,采用的是SIMS公式,(rolling force calculation)
- 2010-06-13 18:35:53下载
- 积分:1
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Program
矩阵转换问题
行与列的个数均为n 的矩阵称为n 阶方阵。假定矩阵中的每个元素的值在0到9之间,则可以将矩阵中的所有元素按行依次排列得到一个“单行矩阵字符串”。(Matrix conversion, the number of rows and columns of the matrix n are called n-order square. Assume that each element of matrix value in the 0 to 9, you can press all the elements of the matrix rows in order of priority for a " single matrix string." )
- 2010-12-28 11:42:08下载
- 积分:1
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最优化作业C++源代码
用C++编的一些最优化作业中的程序,有Newton法,DFP法,共轭梯度法,单纯形法,内点法,外点法,内外点法,都能使用,我已经全部调试过了(C compile some of the most optimized operating procedures, Newton, DFP, conjugate gradient method, the simplex method, interior point method, the points outside the law, outside point method can use, I have all over Debugging)
- 2021-03-29 10:49:11下载
- 积分:1
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1
说明: 一维黎曼问题,一维问题,即激波管问题,是一个典型的一维可压缩无黏气体动力学问题,并有 解析解。对它采用二阶精度两步差分格式进行数值求解。(Riemann problem, One dimensional problem, the shock tube problem, is a typical one-dimensional compressible non viscous gas dynamic problem with analytic solutions. It is solved numerically by two order two step difference scheme.)
- 2018-04-29 14:56:36下载
- 积分:1
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CODE_SOLIDIFICATION
基于热焓法的凝固传热模拟的UFluent-UDF程序(UDF for Modelling Soldification using Enthalpy Porosity Technique)
- 2021-04-16 20:08:53下载
- 积分:1
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JDJSQ
这是一个最最简单计算器,提供给大家参考一下(dadasddasdasd fafdsafasfafad)
- 2012-03-16 15:48:54下载
- 积分:1
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Rongekutta
四阶龙格库塔法函数更新四元数程序代码,采用VC编写(Fourth-order Runge-Kutta method function is updated quaternion code)
- 2010-03-03 21:53:15下载
- 积分:1
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Computational-multibody-dynamics
研究生动力学课程,计算多体动力学课程,
学习起来有点难度,如果有兴趣就看看吧(Graduate dynamics course)
- 2016-03-18 20:36:34下载
- 积分:1
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areaofcircle
一圆形游泳池如图所示,现在需在其周围建一圆形过道,并在其四周围上栅栏。
栅栏价格为35元/米,过道造价为20元/平方米。
过道宽度为3米,
游泳池半径由键盘输入。
要求编程计算并输出过道和栅栏的造价。(A circular pool as shown in figure, now in its built around to a circular corridor, and in its 4 around on the fence.
The fence for 35 yuan/m price, corridor cost for 20 yuan/square metre.
Aisle width is 3 meters,
The radius of the swimming pool by keyboard input.
Demand and output programming calculation of corridor and the cost of the fence.
)
- 2012-04-06 11:29:01下载
- 积分:1