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SR
说明: 基于labview的语音识别播报功能,可以参考(Voice broadcasting function based on LabVIEW)
- 2019-04-18 18:35:05下载
- 积分:1
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tiny.vn_1.2.1
This is the perfect game company game PCK file to see the source code
- 2018-07-14 22:31:53下载
- 积分:1
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DataAccessServer
OPC DA Server 2.0的实现,实现了异步及订阅的方式(The implementation of OPC DA Server 2 implements asynchronous and subscription methods)
- 2017-11-22 17:31:46下载
- 积分:1
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Lua程序设计(第2版)中文
Lua编程入门书籍,Lua程序设计第二版(中文版)(Lua Programming Introduction Book, Lua Programming (Chinese Edition))
- 2020-06-25 04:00:02下载
- 积分:1
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小提琴图 (1)
说明: The source code of data analysis using R language does not contain data sets. If you need to contact us
- 2019-02-23 14:46:45下载
- 积分:1
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含并、交和差运算的集合类型
含并、交和差运算的集合类型- Contains and, hands over with the difference operation set type
- 2023-02-27 11:55:04下载
- 积分:1
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程序目的: 输入一个任意大小的迷宫,用栈求出一条走出迷宫的路径,并 显示在屏幕上。 程序实现: 可以实现载入迷宫和保存迷宫,附带文件中有4个测试迷宫路径的 文件...
程序目的: 输入一个任意大小的迷宫,用栈求出一条走出迷宫的路径,并 显示在屏幕上。 程序实现: 可以实现载入迷宫和保存迷宫,附带文件中有4个测试迷宫路径的 文件test1~4.dd。请将这些文件拷贝到TC当前目录下,或者在载 入时写明完全路径。由于屏幕大小的限制,当用户自己输入迷宫 时一定要注意:迷宫大小是有限制的,不小于4*3,不大于30*20。 否则会出现错误信息。输入开始时全是墙,用上下左右键移动, 用Del键删除墙,形成通路,用Enter键添加墙。输入结束时可以 将迷宫保存下来,以dd为扩展名。输入完毕时用F9键来得到结果, 找到路径时,屏幕下方会出现Path found,否则出现Path not found。 程序经Turbo C 2.0编译调试成功。运行时不用添加任何运行库。 不可以在VC上编译。-procedures purpose : to bring in a maze of arbitrary size, with a stack get out of the maze of trails and on the screen. Program : can achieve and preserve the printed maze maze, the accompanying documents were four test maze of trails to document test1 4.dd. I would be grateful if those files are copied to the TC current directory, or in the state when fully contained path. Due to restrictions on the size of the screen when the user input labyrinth must pay attention to : the size of the maze is a restriction, not less than 4* 3, not more than 30* 20. Otherwise there will be a wrong message. At the beginning of the importation of a
- 2022-08-06 12:51:19下载
- 积分:1
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JZZF
用于20以内的常见进制转换,二进制、八进制、十进制、十六进制的相互转换。(Common base conversion for less than 20.)
- 2018-01-09 10:12:13下载
- 积分:1
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我选择约瑟夫问题(附带一个合数段的问题这是我们第一次的考试题)做我最后一个上传的代码。因为这是我付出最多的一个,我的第一个程序,当时全班就我一个弄了出来现在想起...
我选择约瑟夫问题(附带一个合数段的问题这是我们第一次的考试题)做我最后一个上传的代码。因为这是我付出最多的一个,我的第一个程序,当时全班就我一个弄了出来现在想起来都十分高兴。一年以来还做了其他很多小东西,因为太简陋就步多传了,这些足够代表我大一这年的旅程了。希望你们能给我提供一个更大的学习的机会。不久的将来我就会有质量更高的代码上传了。谢谢先-I chose (a few fringe of a problem this is our first examination), the last one so I uploaded code. Because it is up to me to pay the one, my first one procedure, a class I get out now are very happy together. The past year has also done a lot of other little things too shabby on the multi-step, which I adequately represented in this year"s freshman of the journey. I hope you will give me a greater opportunity to learn. The near future, I will have a better quality of the uploaded code. Thank you first!
- 2022-01-30 12:57:52下载
- 积分:1
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Zigbee-location-code
本程序为基于Zigbee TI CC2431芯片的定位程序原代码,供大家参考,欢迎提出建议(This program is based on Zigbee TI CC2431 chip positioning program source code, for your reference, welcome suggestions)
- 2013-05-28 16:05:44下载
- 积分:1