pcmcode

代码说明：

  律u律pcm编码 若输入A律PCM编码器的正弦信号为x(t)=sin(1600πt),采样序列为x(n)=sin(0.2πn),n=0,1,2,…,10，将其进行PCM编码，求出编码器的输出码组序列y(n)。 要求：1) 直接采用A律扩展器函数求解上述问题。 2）使用13折线法近似A律PCM 求解上述问题。 3）计算量化误差。(Law a law pcm coding If the input A-law PCM encoder is sinusoidal signal x (t) = sin (1600πt), for the sample sequence x (n) = sin (0.2πn), n = 0,1,2, ..., 10, it will be PCM coding to obtain the coded output code group sequence y (n). Requirements: 1) directly A-law expander function to solve the above problems. 2) using a 13 fold line approximation A-law PCM to solve the above problems. 3) calculating the quantization error.)

文件列表：

pcmcode
.......\13.m,783,2004-05-23
.......\a.m,481,2005-06-10
.......\exe32.m,390,2005-06-10
.......\u_pcm.m,773,2005-05-27
.......\习题3.doc,61440,2005-06-27