-
neural-work
内含神经网络的一些程序以及相关matlab工具箱的使用方法。(It contains some procedures and related matlab neural network toolbox of usage.
)
- 2013-10-05 23:33:20下载
- 积分：1
-
wm
说明： 中继位置不同 分配功率相同 的放大协同通信 基于蒙特卡洛仿真(Relay different positions assigned the same zoom power cooperative communication based on Monte Carlo simulation)
- 2011-10-16 19:44:13下载
- 积分：1
-
OFDMsystem
基于IFFTFFT的OFDM系统仿真。完整的可运行的代码。信源用randn产生，信道为高斯白噪声，如用其他，可以方便自行修改。(Based on IFFT FFT of OFDM system simulation. Complete code can be run. Generated using randn source, channel for the Gaussian white noise, such as the use of other, you can easily modify.)
- 2010-06-20 20:49:00下载
- 积分：1
-
OFDM_80211_BPSk_rayleigh
OFDM Rayleigh simulation
- 2009-04-15 11:40:46下载
- 积分：1
-
hamming-matlab
实现汉明码的编码和译码，可设定误码位置，查看纠错效果。(Achieve Hamming encoding and decoding, error location can be set to see the error correction effect.)
- 2011-11-14 22:18:00下载
- 积分：1
-
MATLAB-book
一本非常使用的matlab教程 适合初学者学习 (DB algrithm )
- 2011-12-03 10:42:49下载
- 积分：1
-
EE451LAB05-170206019
ds cdma in communication
- 2013-12-03 20:33:41下载
- 积分：1
-
禁忌搜索
说明： 一种亚启发式(meta-heuristic)随机搜索算法，它从一个初始可行解出发，选择一系列的特定搜索方向（移动）作为试探，选择实现让特定的目标函数值变化最多的移动。(A meta-heuristic random search algorithm that starts with an initial feasible solution and selects a series of specific search directions (moves) as heuristics, selecting the moves that achieve the most changes in the value of a particular objective function.)
- 2021-02-24 15:44:36下载
- 积分：1
-
matlab_SpatialCorrelatedImage
说明： 生成具有空间相关性的图像。整幅图像被看作是一个离散的随机场，每个像素都是一个随机变量。对于空间相关性模拟和研究非常有用！(Generated with a spatial correlation images. Whole image is seen as a discrete random field, each pixel is a random variable. For space-related research of simulation and very useful!)
- 2008-08-28 09:05:27下载
- 积分：1
-
Ritz_solution
Ritz法解决-u +u=x 0<x<1，u(0)=0,u(1)=0的有限元边值问题。精确解为u(x)=1/(exp(1)-1/exp(1))*exp(-x)+1/(1/exp(1)-exp(1))*exp(x)+x，基函数为g(i)=sin(i*pi*x)(This matlab code is used to solve the boundary value problem of the differential equation:
-u +u=x 0<x<1，u(0)=0,u(1)=0, where the accurate solution is :
u(x)=1/(exp(1)-1/exp(1))*exp(-x)+1/(1/exp(1)-exp(1))*exp(x)+x)
- 2011-05-30 20:14:35下载
- 积分：1
