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Kriging_model

于 2016-04-23 发布 文件大小:28945KB
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下载积分: 1 下载次数: 19

代码说明:

  Kriging法(克里金法)算法的matlab的实现,可以直接调用。(Kriging method (Kriging method) algorithm of the realization of matlab, can be called directly. )

文件列表:

Kriging_model
.............\channel_data_360_10.mat,1381056,2014-09-16
.............\channel_data_450_10.mat,1105834,2014-09-16
.............\channel_data_90_10.mat,1102344,2014-09-16
.............\concrete_data.mat,2286,2010-11-04
.............\Contents.m,1202,2002-09-05
.............\corrcubic.m,1207,2002-08-06
.............\correxp.m,1039,2002-08-06
.............\correxpg.m,1176,2002-08-06
.............\corrgauss.m,1028,2002-08-06
.............\corrlin.m,1091,2002-08-06
.............\corrspherical.m,1227,2002-08-06
.............\corrspline.m,1868,2002-08-06
.............\dacefit.m,9060,2002-09-04
.............\dsmerge.m,3942,2002-08-06
.............\gridsamp.m,1205,2002-08-06
.............\h.mat,2759825,2013-09-19
.............\h1000.mat,138150,2013-09-20
.............\h270.mat,1381056,2014-09-22
.............\h360.mat,1381056,2014-09-22
.............\h450.mat,1105834,2014-09-22
.............\h90.mat,1102344,2014-09-22
.............\hnew.mat,2148272,2014-09-19
.............\h_180.mat,2148272,2014-09-19
.............\h_270.mat,2150591,2014-09-19
.............\h_450.mat,2152107,2014-09-19
.............\h_450_new.mat,2151907,2014-09-19
.............\h_90.mat,2144446,2014-09-19
.............\lhsamp.m,592,2002-08-06
.............\Main_sections.asv,3912,2014-09-23
.............\Main_sections.m,3912,2014-09-23
.............\plot_hz.asv,2093,2014-09-22
.............\plot_hz.m,2108,2014-09-23
.............\plot_inf.asv,409,2014-09-22
.............\plot_inf.m,409,2014-09-22
.............\predictor.m,4398,2002-08-27
.............\pre_h180.mat,2759150,2014-09-22
.............\pre_h_180.mat,2147479,2014-09-22
.............\regpoly0.m,377,2002-08-06
.............\regpoly1.m,385,2002-08-06
.............\regpoly2.m,789,2002-09-05
.............\R_error.asv,2165,2014-09-22
.............\R_error.m,2155,2014-09-22
.............\samples - full.dat,30402,2013-10-15
.............\samples.dat,432002,2013-10-31
.............\samples1.dat,479999,2013-10-30
.............\test.dat,48096,2013-10-31
.............\tip.txt,119,2014-04-20
.............\Untitled.asv,390,2014-09-22
.............\Untitled.m,395,2014-09-22
.............\Untitled0.m,150,2013-09-20
.............\v_HZ.asv,490,2014-09-22
.............\v_HZ.m,497,2014-09-22

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  • ForK1
    我们的目的是将一个分数拆分成若干个分子是1分母是正整数的分数之和的形式。例如2/3可以拆分成1/2+1/6的形式。这里不考虑顺序,比如1/6+1/2和1/2+1/6相同。 输入p, q, a, n, 其中p/q为分数,对这个分数进行拆分,要求拆分的分数个数不能多于n个,所有分母的乘积不能大于a。求有多少种拆分方法? 输入:最多200组数据。在每行中都有四个数分别表示p, q, a, n,之间以空格隔开,并且满足p,q<=800,a<=12000,n<=7,最后以四个0做为输入的结束。 输入示例: 2 3 120 3 2 3 300 3 0 0 0 0 输出示例: 4 7 (Our aim is to split a fraction into a number of elements is a denominator is a positive integer fraction of the sum of form. For example, 2/3 can be split into 1/2+1/6 form. Not considered here, the order, such as 1/6+1/2 and 1/2+1/6 of the same. Input p, q, a, n, where p/q as a fraction of this split scores require no more than the number of split points n-all the product of the denominator can not be larger than a. How many kinds of demand split method? Input: Up to 200 sets of data. In each line has four numbers indicate the p, q, a, n, separated by a space between, and meet the p, q < = 800, a < = 12000, n < = 7, the end, four 0 as the input end. Input Example: 2,312,032,330,030,000 sample output: 47)
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