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Desktop
调度问题的回溯算法，算法中的经典问题。问题描述：假设有n个任务由k个可并行工作的机器完成。完成任务i需要的时间为ti。试设计一个算法找出完成这n个任务的最佳调度，使得完成全部任务的时间最早。(Scheduling problem backtracking algorithm is the classic problem. Problem Description: Suppose there are n-task by the k-parallel machine can be completed. The time required to complete the task i is ti. Try to design an algorithm to find completing these n-best task scheduling, making the earliest time to complete all tasks.)
- 2010-02-19 23:31:11下载
- 积分：1
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StringDataManage
控制台下的字符串管理程序，并且带有好看的节面（使用其他人的库）(String under the console management program, and with a good-looking face of the section (using other people s libraries))
- 2012-11-22 01:26:14下载
- 积分：1
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tongxinlu
通信录源程序。调试环境为TC2.0或者3.0。运行这个程序需要tc提供的几个头文件。(Example source address book, or 3.0 debugging environment for TC2.0. Tc run the program needs to provide several header files.
)
- 2011-12-05 15:03:16下载
- 积分：1
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changevideomode
自己写的一个检测某个程序是否运行来改变系统分辨率的控制台程序(Writing own a Detect whether a program is running to change the system console resolution procedures)
- 2009-02-26 15:45:57下载
- 积分：1
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jiaobingbu
集合的运算：交、并、补（难度系数：1.1）
全集：大写字母 ‘A’~’Z’
要求实现以下功能：
1、集合的输入：自动去掉重复和非法的字符
2、集合的显示：输出集合的全部元素
3、输出一个给定集合的补集
4、输出两个给定集合的交集和并集
(jiao bing bu)
- 2013-11-29 20:49:25下载
- 积分：1
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Win32Timer
基于Visual C++ 的win32控制台的程序，实现使用定时器的功能，(Visual C++ win32 console-based program, using the timer function,)
- 2012-03-06 14:20:34下载
- 积分：1
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tvicport
在WINDOWS 9X/NT下不通过WIN DDK而直接存取硬件的专用开发包，支持VISUAL C++和DELPHI/C++ BUILDER，需要32位编译器。TVicPort includes transparent support for Windows 95/98 and Windows NT (in Windows 9X/NT under WIN DDK is not passed directly access dedicated hardware development kits, support Visual C and Delphi/C BUILDER need 32 compiler. TVicPort includes transparent support for Windows 95/98 and Windows NT)
- 2005-05-26 10:40:55下载
- 积分：1
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Queue
队列的顺序定义，队列的调用算法等，队列的模板类及其实现(Defined in the order queue, queue calls algorithm, queue template class and its implementation)
- 2013-07-17 15:42:54下载
- 积分：1
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lucky38
hangle unicode used AI
- 2011-08-30 18:34:33下载
- 积分：1
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Triangle
求解符号三角形问题.给定一行符号(比如+和-),按照同号为+异号为-的原则计算第二行直至下面的行,最后的一行只有一个符号,要求统计各个符号的个数.(Problem solving triangle symbols. Given his symbols (such as+ And-), in accordance with the same number is+ Different number- the principle of calculation of the second line until the following line, the last line there is only one symbol, all symbols requested statistics number.)
- 2008-07-15 14:53:58下载
- 积分：1
