登录
首页 » matlab » relativity

relativity

于 2017-10-26 发布 文件大小:1KB
0 351
下载积分: 1 下载次数: 24

代码说明:

  计算图像水平相邻、垂直相邻、对角相邻像素之间的相关性(relativity between pixel of image)

文件列表:

relativity1.m
relativity2.m

下载说明:请别用迅雷下载,失败请重下,重下不扣分!

发表评论

0 个回复

  • Modbus-for-Field-Technicians
    Modbus for Field Technicians 介绍modbus的相当好的资料,包括原理和编程和协议介绍(Modbus for Field Technicians introduction modbus fairly good information, including schematics and programming and protocol description)
    2013-07-13 22:47:57下载
    积分:1
  • 李纯明博B
    说明:  李纯明博士的图像分割源代码,可以分割各种图像,可运行。(Dr. Li Chunming image segmentation source code, can be divided into a variety of images, can run.)
    2020-06-19 18:38:36下载
    积分:1
  • MUSIC
    阵列信号处理的基本MUSIC算法以及改进的基于子空间投影加权的MUSIC算法,以及全空间加权MUSIC算法对DOA进行估计,以及几种算法的均方根误差比较(The basic MUSIC algorithm of array signal processing, the improved MUSIC algorithm based on subspace projection weighted, and the full space weighted MUSIC algorithm for the estimation of DOA, and the root mean square error comparison of several algorithms)
    2020-08-03 16:18:34下载
    积分:1
  • Chapter_14_Programming
    信号分析仪 编程手册主要是基于安捷伦IO 套件应用平台 简单实用的仪器控制编程程序(Signal analyzer e5052a programming manual is mainly based on agilent IO suite application platform Simple and practical instrument control programming procedures)
    2017-07-19 10:20:55下载
    积分:1
  • channel estimation
    说明:  有助于学习LS信道估计的编码,以及mmse和LMMSE(ls chanel MMSE CHANEL LMMSE CHANEL)
    2019-04-12 12:38:27下载
    积分:1
  • IOT_Simulation_3_BasicModels
    opnet 仿真,陈敏老师2015年新书 opnet物联网仿真(opnet Simulation)
    2020-09-22 22:47:49下载
    积分:1
  • 5_Name
    数组可以存放5个人的姓名,每个姓名包括first name,middle name和last name,输出姓名时,其中middle name只取大写的首字母,利用索引编写程序,使得用户输入last name后,输出姓名的全称。(array can store the names of five individuals, including the names of each first name, middle name and last name, the name of the output, which only middle name from the first uppercase letter, the use of indexing programming, enabling users to import last name, the name of the generic output.)
    2005-05-27 10:10:19下载
    积分:1
  • 4
    说明:  :载波频率偏移是OFDM系统实现的关键问题之一。分析了OFDM 系统载频偏移估计的2 种算法,即利用循环前缀和训练序列方法。它们均为最大似然估计方法。分别讨论了它们的基本 思想、实现方法和仿真结果。可以看出基于循环前缀算法复杂度较小,精度不高,而基于训练序列 的算法有较高的估计精度,但降纸了系统传输效率。(Abstract:Carrier frequency ofset is one of the key problems in OFDM system.Two foundational methods 。cycling prefix—based and training sequence—based algorithms。to estimate OFDM carriers~equency ofset are analyzed.Then it discusses their basic thoughts。implementing methods and simulation resuits. Finally。merits and demerits of every algorithm are supposed.It concludes that the cycling prefix— based algorithm has less complexity and less precision。and that the training sequence—based algorithm has better estimation performance at the cost of transmission efficiency.)
    2010-05-18 18:34:44下载
    积分:1
  • fwdmalawmc
    Abstract—In this paper, we study the joint estimation of inphase and quadrature-phase (I/Q) imbalance, carrier frequency offset (CFO), and channel response for multiple-input multipleoutput (MIMO) orthogonal frequency division multiplexing (OFDM) systems using training sequences. A new concept called channel residual energy (CRE) is introduced. We show that by minimizing the CRE, we can jointly estimate the I/Q imbalance and CFO without knowing the channel response. The proposed method needs only one OFDM block for training and the training symbols can be arbitrary. Moreover when the training block consists of two repeated sequences, a low complexity two-step approach is proposed to solve the joint estimation problem. Simulation results show that the mean-squared error (MSE) of the proposed method is close to the Cramer-Rao bound (CRB). Index Terms—MIMO OFDM, CFO, I/Q imbalance, channel estimation.
    2012-03-29 16:33:58下载
    积分:1
  • jiugongwenti
    (九宫问题)在一个3×3的九宫中有1-8这8个数及一个空格随机的摆放在其中的格子里,如图1-1所示。现在要求实现这个问题:将该九宫格调整为如图1-1右图所示的形式。调整的规则是:每次只能将与空格(上、下、或左、右)相邻的一个数字平移到空格中。试编程实现这一问题的求解。((Nine-palace issues) in a 3 × 3 of the Nine-palace are 1-8 this 8 random number and the placing of a space in which the cell house, as shown in Figure 1-1. Now required to achieve this issue: the squares adjustment for the right as shown in Figure 1-1 form. Adjustment of the rules: each can only be with the spaces (upper and lower, or left, right) adjacent to a digital flat space. Test Programming to solve this problem.)
    2008-12-25 22:07:50下载
    积分:1
  • 696516资源总数
  • 106611会员总数
  • 19今日下载