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1
说明： 电力系统潮流上机程序，已知线路结构，pq节点，pv节点和平衡节点，求各点的未知量。(Power System Power program, known line structure, pq node, pv nodes and balancing node, find the unknown amount of points.)
- 2011-05-13 22:11:28下载
- 积分：1
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Note8_Dcm_debug_note
汽车开放式架构Autosar 中的诊断通信模块的调试笔记。(The doc is the debug note for the Dcm moude in the AUTOSAR .)
- 2014-08-12 17:30:43下载
- 积分：1
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8neddemo
入门omnet++,omnet++仿真实验，欢迎大家一起交流。(It is very useful for student who study omnet++.)
- 2010-01-09 22:04:06下载
- 积分：1
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gg_mle
这是对广义高斯分布中两个参数alpha,beta的估计方法，对自然图像的大量统计特征就符合这一分布。(function [f, g] = dggbeta(beta, absx)
DGGBETA Derivative of generalized Gaussian pdf with respective to beta
[F, G] = DGGBETA(BETA, ABSX)
Return partial derivative and second order partial derivative
This is an utility function for GGMLE
ABSX is the distance of the data from the mean
Function is undefined for negative beta
if beta <= 0
f = NaN
g = NaN )
- 2013-03-15 10:37:51下载
- 积分：1
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A3
说明： Osada算法A3距离实现。C与matlab混合编程。(Osada algorithm A3 distance. C and matlab mixed programming.)
- 2012-10-21 10:53:05下载
- 积分：1
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dizhenginedex
这是一篇地震的数学理论方面的文章，希望能对大家有帮助(This is a mathematical theory of an article of the earthquake, I hope you can help)
- 2015-03-26 10:03:19下载
- 积分：1
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millimeter-wave
子波高分辨谱估计方法及其在毫米波雷达目标一维距离成像中的应用(Wavelet resolution spectral estimation method and its application in the millimeter-wave radar target from imaging)
- 2013-12-25 18:51:41下载
- 积分：1
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backwardforward
backwardfoeward load flow for distribution network
- 2014-02-14 00:30:57下载
- 积分：1
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5
一道程序编译顺序的考题，涉及到函数调用的先后顺序及运算符号的优先级等问题。下面我展开给你讲。
C的程序编译总是从main函数开始的，这道题的重点在“fun（（int）fun（a+c,b）,a-c）） ”语句。
系统首先要确定最外层 fun()函数的实参，第一个参数的确定需要递归调用fun()函数（不妨称其为内层函数）。内层函数的两个参数分别为x=a+b=2+8=10、y=b=5,执行函数体x+y=10+5=15,于是得外层函数的参数x=15。其另一个参数y=a-c=2-b=-6,再次执行函数体,得最终返回值x+y=15+(-6)=9。 (Compiling together the sequence of test procedures, involving the sequence of function calls and operator symbols, such as the priority problem. Now I give you to start speaking. Procedures for C compiler always start from the main function and at这道题the focus of " fun ((int) fun (a+ c, b), ac)) " statement. System must first determine the most outer layer of fun () function of real parameters, the first parameters of recursive calls required fun () function (may be called the inner function). Inner function separately for the two parameters x = a+ b = 2+8 = 10, y = b = 5, to execute the function body x+ y = 10+5 = 15, then the outer function parameters were x = 15 . Its another parameter y = ac = 2-b =- 6, once again to execute the function body may eventually return the value of x+ y = 15+ (-6) = 9.)
- 2009-03-15 15:36:23下载
- 积分：1
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RamFunction
一个ram例子，可以参考一下，希望能帮到你，请用winrar解压缩打开。(A ram example, you can refer to, I hope you can help, please use winrar to decompress opened.)
- 2013-11-13 13:44:13下载
- 积分：1
