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0728-0708-0704

于 2021-03-14 发布 文件大小:9085KB
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  北邮数据结构课程设计大作业之旅行模拟查询系统。可实现多线程多旅客、中途更改计划、动态显示旅客状态等多个需求。已通过验收。(BUPT curriculum design travel query system simulation of large operations. Multithreading enables passengers to change plans midway, dynamic display multiple demands guest status. It has passed inspection.)

文件列表：

0728-0708-0704
..............\document
..............\........\功能需求说明及分析.doc,28160,2016-06-03
..............\........\各模块设计说明.docx,53777,2016-06-03
..............\........\总体方案设计说明.doc,19456,2016-06-03
..............\........\数据结构说明和数据字典.doc,52224,2016-06-02
..............\........\用户使用说明.docx,736357,2016-06-03
..............\........\范例执行结果及测试情况说明.docx,7026063,2016-06-03
..............\........\设计任务的描述.doc,15872,2016-06-03
..............\........\评价和改进建议.docx,18432,2016-06-03
..............\report.docx,13604,2016-06-03
..............\report1.txt,1141,2016-06-06
..............\report2.txt,0,2016-06-06
..............\report3.txt,0,2016-06-06
..............\run.exe,1892451,2016-06-03
..............\source_code
..............\...........\ControlFun.cpp,44934,2016-06-02
..............\...........\ControlFun.h,1574,2016-06-02
..............\...........\Debug
..............\...........\.....\时刻表.mdb,352256,2016-05-25
..............\...........\res

..............\...........\...\TravelPlan.rc2,402,2009-03-03


..............\...........\resource.h,3995,2016-05-29
..............\...........\StdAfx.cpp,227,2009-03-25
..............\...........\StdAfx.h,1232,2009-03-25
..............\...........\TravelPlan.cpp,2343,2009-03-26
..............\...........\TravelPlan.dsp,4571,2016-05-29
..............\...........\TravelPlan.dsw,528,2016-05-29
..............\...........\TravelPlan.h,512,2016-05-24
..............\...........\TravelPlan.rc,19806,2016-06-03
..............\...........\TravelPlanDlg.cpp,58131,2016-06-03
..............\...........\TravelPlanDlg.h,2817,2016-06-02
..............\时刻表.mdb,352256,2016-05-25

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  • NoGo
    计算机博弈大赛不围棋的代码 个人所写，可以用来参考( U8BA1 u7B97 u673A u535A u5F08 u5927 u8D5B u4E0D u56F4 u68CB u7684 u4EE3 u7801 u4E2A u4EBA u6240 u5199 uFF0C u53EF u4EE5 u7528 u6765 u53C2 u8003)
    2021-04-04 19:39:04下载
    积分：1
  • jiaotong
    用于课程设计 利用Dijkstra算法进行简单的最短路径查询 (For curriculum design simple shortest path query)
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    VC游戏编写中的求解最短路径算法源码，本示例是自动寻径演示，篮点是起点，红点是终点，按确定键开始。源码爱好者注：编译后运行的时候请把EXE文件从Debug目录中拷贝到项目根目录中，若不然会出错。 (The preparation of the VC games to solve the shortest path algorithm source code, in this example is the automatic routing demonstration, the basket is the starting point, the red dot is the end point, press the OK button to start. Source enthusiasts Note: When compiled and run, please copy the EXE file from the Debug directory to the root directory of the project, and if not be wrong.)
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    说明：  进程死锁.资源分配图的绘制 建立所需数据结构；  使用题目21存成的资源分配图的文件作为输入；  编写资源分配图化简算法；  每化简一步，在屏幕上显示化简的当前结果；  最后给出结论，是否死锁，如思索给出死锁的进程及资源； (Process deadlock. Resource allocation mapping  establish the required data structures  Use title 21 deposit into resource allocation graph file as input  writing resource allocation map simplification algorithm  Each simplification step, on-screen display simplification of the current result  Finally, the conclusion of a deadlock, deadlock is given as thinking processes and resources )
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    说明：  操作系统先来先服务调度算法模拟（C描述）(Operating a first-come first-served scheduling simulation (C description))
    2010-04-13 00:02:35下载
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