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5.2.3
matlab源代码 基于MATLAB的Reed_Muller码编译码仿真(matlab source code based on MATLAB' s Reed_Muller decoding simulation)
- 2010-07-16 01:09:42下载
- 积分:1
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TestActiviti
基础的activity引擎测试demo实例(basic activity demo)
- 2014-09-18 11:17:17下载
- 积分:1
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kunlao
有PMUSIC 校正前和校正后的比较,MIMO OFDM matlab仿真,相控阵天线的方向图(切比雪夫加权)。( A relatively before correction and after correction PMUSIC, MIMO OFDM matlab simulation, Phased array antenna pattern (Chebyshev weights).)
- 2017-02-25 11:40:38下载
- 积分:1
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8Inverse-Fisher-discriminate-
8Inverse Fisher discriminate criteria for small sample size problem and its application to face recognition 2005-Zhuang-Dai
- 2014-10-22 20:45:27下载
- 积分:1
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MATLAB
matlab神经网络30个算法详细的解释和介绍。有的也是用c++描述的(30 matlab neural network algorithm detailed explanation and presentation. Some also described using c++)
- 2015-01-06 12:25:44下载
- 积分:1
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LMS_matlab
这个是用MATLAB程序编写的回波消除的代码,效果不错,简单明了(This is a MATLAB programming with the echo cancellation code, the effect is good, simple and clear)
- 2014-02-24 19:53:50下载
- 积分:1
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differentialDrive.pdf
This is related to kinematics for differential drive motors....
- 2011-04-25 20:06:29下载
- 积分:1
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inmin01
用积分最小值准则来求P,PI,PID的个参数,其中Gc是校正器的传递函数,kp为比例系数, Ti为积分时间常数,Td为微分时间常数,输入参量vars为带迟滞--惯性环节模型的[K T τ],已知参数k=vars(1);T=vars(2);ι=vars(3),iC=vars(4) (Minimum criteria of integral seeking P, PI, PID' s parameters, which Gc is the corrector transfer function, kp is proportional coefficient, Ti for the integral time constant, Td for the differential time constant, input parameters vars as with hysteresis- inertia model of [KT τ], known parameters k = vars (1) T = vars (2) ι = vars (3), iC = vars (4) )
- 2010-05-18 20:35:38下载
- 积分:1
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jsgd-61
该代码采用matlab和C混合编写,是采用随机梯度的方法训练线性分类器,它可用于数据、图像等的多类分类情况。参考论文:Good Practice in Large-Scale Learning for Image Classification(This a Stochastic Gradient Descent algorithm used to train linear multiclass classifiers. It is biased towards large classification problems (many classes, many examples, high dimensional data).)
- 2013-09-03 16:42:11下载
- 积分:1
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07027162
IMPARARE IL C++ in 2 ore e mezzo?
Modulo-000
- 2015-03-10 23:22:16下载
- 积分:1