-
jiguangcar
激光小车引脚请自行修改我靠 还要我写多少字？(Laser trolley pin please modify how much I rely want me to write the word?)
- 2013-10-30 16:39:17下载
- 积分：1
-
jingtai
捷联惯惯性导航的C程序实现，四元数表示姿态，静态下进行试验，MATLAB进行图像处理，包含原始数据。(Strapdown inertial navigation of the C programs used to achieve, said the attitude quaternion, static tests under, MATLAB for image processing, including raw data.)
- 2009-12-01 14:36:59下载
- 积分：1
-
Elingcs
EXCEL精灵 反编译原代码 ，这段代码幸亏不是全球数据，要不会把编译器气冒烟的(EXCEL Wizard Decompiles Original Code)
- 2020-06-21 21:00:02下载
- 积分：1
-
华为校园招聘笔试面试题合集
华为校园招聘合集，各个岗位的的笔试题,非常有用(good book is good book)
- 2018-03-20 21:50:52下载
- 积分：1
-
huaweiCPP(CHM)
华为C++培训资料C++语言中级教材讲授C++语言的运用技术，包括：类、对象之间的关系、对象的存储与布局、运算符重载、智能指针、仿函数、泛型编程，C++模式设计基本思想。
(C++ language intermediate materials to teach C++ language use of technology, including: classes, relationships between objects, object storage and layout, operator overloading, smart pointer, functor, generic programming, C++ mode design basic idea.)
- 2013-05-05 16:53:08下载
- 积分：1
-
acoustic forward - 4
二维声波方程正演模拟时间二阶，空间12阶交错网格正演模拟(Forward modeling of two-dimensional acoustic wave equation with time two order and space 12 order staggered grid forward modeling)
- 2017-10-29 20:50:35下载
- 积分：1
-
link
连连看 小游戏 可以进行几本的连连看，玩得比较爽，看上去比较舒服(the little games，it is very good)
- 2013-09-28 22:55:09下载
- 积分：1
-
radar matlab
里面有包含雷达方程的一些matlab程序以及对应画图的相关程序(radar equation matlab procedure)
- 2020-07-02 04:40:01下载
- 积分：1
-
Calculator
说明： 一个复杂的智能计算器，可以实现智能计算，以及优先级判断(A complex smart calculator, you can achieve intelligent computing, as well as to determine priority)
- 2010-03-25 12:05:50下载
- 积分：1
-
最佳适应算法 信安 陆华锋 20022638
最佳适应算法是动态内存分区分配算法的一种。所谓“最佳”是指每次为作业分配内存时，总是把能满足要求、又是最小的空闲分区分配给作业，避免“大材小用”。为了加速寻找，该算法要求将所有的空闲分区按其内容以从小到大的顺序形成一空闲分区链。这样，第一次找到的能满足要求的空闲区，必然是最佳的。(best adaptation algorithm is a dynamic memory allocation through an algorithm. The so-called "best" means the operation of each memory allocation, always meet requirements, and also the smallest area allocated to idle operations, to avoid "a waste of talent." To speed up the search, the algorithm requires that all leisure district according to content from small to large order of the formation of a regional chain idle. So, the first found to meet the requirements of the free zone will be the best.)
- 2005-07-04 08:18:40下载
- 积分：1
