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visible_light
可见光通信代码仿真。可以在matlab上进行matlab仿真。(Visible Optical Communication Simulation Code)
- 2021-04-19 23:38:50下载
- 积分:1
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DAB_TEST
说明: 仿真实现了DAB的移相控制效果,可用于DAB控制的开发与运行特性分析。(The simulation realizes the effect of phase-shift control of DAB, which can be used for the development and operation characteristic analysis of DAB control.)
- 2020-11-20 00:19:37下载
- 积分:1
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用C语言编写短消息SMS时,需要用的Unicode编码到gb2312编码转化关系表...
用C语言编写短消息SMS时,需要用的Unicode编码到gb2312编码转化关系表-Unicode to gb2312
- 2022-01-25 17:33:22下载
- 积分:1
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C
说明: 学生信息管理系统 大三课程设计做得 非常简单 可以看看(cc)
- 2010-01-05 08:42:59下载
- 积分:1
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数根
数也有根吗?有!数根就是把一个数的各个数位上的值相加,直到得到一个一位数为止。请你编写一个程序来计算任意数N(0≤N≤1000000000000)的...
数根
数也有根吗?有!数根就是把一个数的各个数位上的值相加,直到得到一个一位数为止。请你编写一个程序来计算任意数N(0≤N≤1000000000000)的根。
输入:
输入有多个案例。每一个案例为一行,每行只有一个整数N。当输入的N是-1时,输入结束。
输出:
每一个案例输出一行。每行只有一个数字,就是N对应的数根。
Sample input
39
-1
Sample output
3-Number of root number also has roots do? There is! The number of roots is to a number of different values on the digital sum until they have been a number of up to one. Please write a program to calculate an arbitrary number N (0 ≤ N ≤ 1000000000000) roots. Input: Enter a number of cases. Each case for the line, each line is only an integer N. When the input of N is-1, the input end. Output: the output line of each case. There is only one number per line, that is, N corresponds to the number of roots. Sample input 39-1 Sample output 3
- 2023-09-05 21:25:03下载
- 积分:1
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game-theory-of-spectrum-allocation
Matlab program based on game theory of spectrum allocation
- 2012-07-20 13:03:14下载
- 积分:1
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83390053PID-Tuning-using-DE
differential evalution algorithm for tuning pid controller
- 2018-02-13 13:08:47下载
- 积分:1
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nandflash的电子硬盘详细设计资料,方便你将disk-on-chip嵌入到你自己的应用系统中-nandflash electronic disk detailed design information, You will facilitate disk-on-chip embedded into your own application system
- 2022-01-21 19:16:53下载
- 积分:1
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《爱上Arduino》中文版
教程很不错,我虽然学的单片机是51,但是这个也适合自己摸索(It is good.Though I learn 51,it is suitable for us to do experience.)
- 2017-12-24 10:15:11下载
- 积分:1
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计算图中两点间最短路径和距离
calculates the shortest path and distance between two nodes on a map
- 2023-04-22 13:00:03下载
- 积分:1