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111
对加速度数据进行二次积分,最终得到位移数据。(Double integration of acceleration data and the final displacement data.)
- 2020-11-27 15:59:30下载
- 积分:1
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PolyFractionValu
本程序提供大量实用多项式计算函数:求一维实(复)多项式值、求一维多项式组值、求二维实(复)多项式值、两一维多项式相乘、两一维多项式除法、计算连分式函数值。(look it yourself.)
- 2021-02-19 10:19:44下载
- 积分:1
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test_read_file
实现了对文档的数据读入,实现了文档的数据读入(The realization of the document data read into, The realization of the document data read into, )
- 2013-08-14 02:15:23下载
- 积分:1
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hardware
FFT变换,有硬件说明架构和框图,说明傅里叶变换的原理和意义,同时附有128点的傅里叶变换(FFT )
- 2013-03-17 13:38:52下载
- 积分:1
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Burden_solution
数值分析(Burden)第七版的习题解答,中文繁体,找不到简体的,大家凑合看吧(Numerical Analysis (Burden) answers to the seventh edition of the exercises, Chinese Traditional, can not find the simplified)
- 2021-03-09 22:49:27下载
- 积分:1
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buitei
已经调试成功.内含m文件,可直接运行,迭代自组织数据分析,仿真图是速度、距离、幅度三维图像。( Has been successful debugging. M contains files can be directly run, Iterative self-organizing data analysis, FIG simulation speed, distance, amplitude three-dimensional image.)
- 2016-09-17 11:32:28下载
- 积分:1
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smallest
这是数值计算当中最小二乘法的例子,在matlab中实现(This is the numerical calculations of the least squares method, for example to achieve Matlab)
- 2006-06-07 23:54:29下载
- 积分:1
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burg
matlab程序—用burg方法计算太阳黑子爆发的周期(the matlab program-the frequency of the sunspot by the method of burg)
- 2013-07-20 22:51:57下载
- 积分:1
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Matrix Computations 4th edition.pdf
说明: 矩阵计算英文版第4版,经典,经典,很不错!!!!!请下载!!!!!!(Matrix Computing English Version 4, classic, classic, very good!!!! Please download!!!!!!)
- 2020-06-23 22:20:02下载
- 积分:1
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11087 统计逆序对
说明: Description
设a[0…n-1]是一个包含n个数的数组,若在ia[j],则称(i, j)为a数组的一个逆序对(inversion)。
比如 有5个逆序对。请采用类似“合并排序算法”的分治思路以O(nlogn)的效率来实现逆序对的统计。
一个n个元素序列的逆序对个数由三部分构成:
(1)它的左半部分逆序对的个数,(2)加上右半部分逆序对的个数,(3)再加上左半部分元素大于右半部分元素的数量。
其中前两部分(1)和(2)由递归来实现。要保证算法最后效率O(nlogn),第三部分(3)应该如何实现?
此题请勿采用O(n^2)的简单枚举算法来实现。
并思考如下问题:
(1)怎样的数组含有最多的逆序对?最多的又是多少个呢?
(2)插入排序的运行时间和数组中逆序对的个数有关系吗?什么关系?
输入格式
第一行:n,表示接下来要输入n个元素,n不超过10000。
第二行:n个元素序列。
输出格式
逆序对的个数。
输入样例
5
2 3 8 6 1
输出样例
5(Set a[0... N-1] is a n array containing n numbers. If there is a [i] > a [j] i n the case of I < j, then (i, j) is a n inversion pair of a array.
For example, has five reverse pairs. Please use the idea of "merge sorting algorithm" to achieve the statistics of inverse pairs with O (nlogn) efficiency.
The number of inverse pairs of a sequence of n elements consists of three parts:
(1) The number of reverse pairs in the left half, (2) the number of reverse pairs in the right half, (3) the number of elements in the left half is greater than that in the right half.
The first two parts (1) and (2) are implemented by recursion. To ensure the final efficiency of the algorithm O (nlogn), how should the third part (3) be implemented?
Do not use O (n ^ 2) simple enumeration algorithm to solve this problem.)
- 2019-01-07 23:52:06下载
- 积分:1