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gaijinban
可以识别火焰 将火焰定位出来 背景复杂也可以使用(The flame can identify the flame with a complex background and can be used)
- 2018-01-15 10:59:18下载
- 积分：1
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观察者模式-老板回来04
本源码为利用C#与EMGUCV调用摄像头，从而达到截屏的目的(The source code is to use C # and EMGUCV to call the camera, so as to achieve the purpose of screen capture.)
- 2020-06-24 12:40:02下载
- 积分：1
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matlab slx
说明： 利用matlab的simulink完成了倒立摆的LQR仿真，能实现位置跟踪，效果很不错(Matlab simulink completed the inverted pendulum LQR simulation, can achieve the position tracking, the effect is very good.)
- 2020-03-18 10:41:13下载
- 积分：1
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测试UDPTCP数据包,用于调试数据，及大容量数据测试
测试UDPTCP数据包,用于调试数据，及大容量数据测试-UDPTCP test packets of data for debugging, and testing high-capacity data
- 2023-04-30 22:00:04下载
- 积分：1
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Hseries_3Level_Inverter_No1
三电平逆变器的Simulink模型，调制方式采用SPWM。(The Simulink model of three-level inverters adopts SPWM as its modulation mode.)
- 2020-10-12 22:37:34下载
- 积分：1
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ActiveMQ.part05
说明： ActiveMQ服务，简单直接启动即可，方便测试，第五部分(ActiveMQ service, simple and direct start, easy to test, Part 5)
- 2020-06-17 09:40:01下载
- 积分：1
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基于c语言实现的的流星雨
说明： C语言课程设计——基于C语言实现的的流星雨(the meteor shower by C language)
- 2020-11-17 16:45:37下载
- 积分：1
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amp_bianpin.m
说明： 利用连续小波变换实现对地震信号的拓频
本程序可以实现对高频小波系数的提取、放大(Using continuous wavelet transform to expand the frequency of seismic signal)
- 2020-04-13 10:55:32下载
- 积分：1
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自己做的一款手机RPG游戏
虽然不是很好
但是值得新手
自己做的一款手机RPG游戏
虽然不是很好
但是值得新手-Own a cell phone to do the RPG Game, though not very good but it is worth novice
- 2023-01-29 06:40:04下载
- 积分：1
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Single round robin tournament players winning sequence to solve the problem name...
单循环赛中选手胜负序列求解问题
名称：单循环赛中选手胜负序列求解问题
内容：有n个选手 P 1 ,P 2 ,P 3 ,… ,P n 参加了的单循环赛，每对选手之间非胜即负。现要求求出一个选手序列 P 1 ,P 2 ,P 3 ,… ,P n , 使其满足 P i 胜 P i+ 1 (i=1,… ,n-1) 。
-Single round robin tournament players winning sequence to solve the problem name: the outcome of single round-robin tournament players to solve the problem sequence elements: There are n-player P 1, P 2, P 3, ..., P n participated in a single round-robin between each pair of players Non-win or negative. Players are now required to find a sequence of P 1 " , P 2" , P 3 " , ..., P n" , to meet the P i " W P i+ 1" (i = 1, ..., n-1).
- 2022-04-01 08:15:51下载
- 积分：1
