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XDS100v3-Design-Kit-1.0-Setup
说明: 仿真器开发资料。TI新一代仿真器XDS100V3.(Simulator development data. TI new generation simulator XDS100V3.)
- 2019-03-18 19:34:40下载
- 积分:1
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1998-J.H.-Stock--M.W
1998-J.H. Stock, M.W. Watson Business Cycle fluctuations in US macroeconomic time series.pdf
- 2012-05-03 19:21:15下载
- 积分:1
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F405_PCA9685_test
For PCA9685.
STM32F405 is needed
- 2019-02-01 23:23:34下载
- 积分:1
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mysql数据库的驱动程序压缩包,下载后,就可用于myeclipse和mysql的连接...
mysql数据库的驱动程序压缩包,下载后,就可用于myeclipse和mysql的连接-Mysql database driver compressed package,After download, it can be used to myeclipse and mysql connection
- 2022-01-25 14:07:57下载
- 积分:1
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CrossGame
利用cocos2d-x引擎制作的十字消除类,益智游戏(Use cocos2d-x engine produced Cross eliminate class, puzzle games)
- 2013-10-09 08:48:38下载
- 积分:1
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Bandwidth
Expirmental Evaluation
- 2017-08-15 21:53:48下载
- 积分:1
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真的很麻烦也,有必要这样吗?搞错没有啊?快让我下
真的很麻烦也,有必要这样吗?搞错没有啊?快让我下-really have trouble, it is necessary to do? Ah no wrong? Let me quickly under!
- 2022-04-13 10:59:42下载
- 积分:1
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入侵检测系统snort,代码纷繁复杂,程序文件很多,对于新手,很难分析清楚源代码,但是源代码确实研究入侵检测系统分场重要的工具。
本资料详细分析了入侵检测...
入侵检测系统snort,代码纷繁复杂,程序文件很多,对于新手,很难分析清楚源代码,但是源代码确实研究入侵检测系统分场重要的工具。
本资料详细分析了入侵检测系统snort的体系结构,程序源代码,主要数据结构和重要函数。-Intrusion Detection System snort, complex code, a lot of program files, for novices, it is difficult to analyze the source code, but the study of the source code is indeed an important breakout intrusion detection system tools. A detailed analysis of the information system snort intrusion detection architecture, the program source code, the main data structure and an important function.
- 2022-11-03 13:05:04下载
- 积分:1
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LaTeX_Learning
Latex教程,东北大学薛定宇教授编著,一本相当不错的参考书(Latex tutorials, Professor Xue Dingyu, Northeastern University, has compiled a pretty good reference
)
- 2012-03-12 17:18:09下载
- 积分:1
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CrossRiver
有N个传教士和N个野人要过河,现在有一条船只能承载K个人(包括野人),K<N,在任何时刻,如果有野人和传教士在一起,必须要求传教士的人数多于或等于野人的人数。
设M为传教士的人数,C为野人的人数(There are N missionaries and N savages crossing the river. Now a boat can only carry K individuals (including savages), K < N. At any time, if there are savages and missionaries together, the number of missionaries must be more than or equal to the number of savages. Let M be the number of missionaries and C the number of savages.)
- 2020-06-17 17:20:02下载
- 积分:1