-
renwufenpei
任务分配问题，这是一个算法，c语言类型的，讲述如何进行多个房间的任务分配(Task allocation problem, which is an algorithm, c language type, tells how to assign multiple tasks room)
- 2014-04-18 12:35:15下载
- 积分：1
-
duffing
duffing振子的安全盆做法,运用Fortran软件运行，很方便，很实用，对学习非线性方面的同学很有帮助(duffing osillator for the safe basin)
- 2012-10-16 21:52:22下载
- 积分：1
-
WDEB386_Debugger
The Windows 95 Device Driver Kit
WDEB386 System Debugger
- 2007-11-08 00:05:35下载
- 积分：1
-
GetWindowsPassWord
该程序用于在用户登陆状态下获取用户的登陆密码。原理是windows 2003 将用户的密码存储在 lsass.exe 的指定偏移的内存中。通过对该进程内存的扫描即可获取系统密码。(the procedure for landing on a user's state of the user's password landing. The principle is windows 2003 to the password stored in the designated offset lsass.exe memory China. Through the process of memory can be obtained by scanning system password.)
- 2006-10-26 10:46:03下载
- 积分：1
-
简单的FTP客户类
简单的FTP客户类-simple FTP client categories
- 2022-03-22 02:18:45下载
- 积分：1
-
homework1
一维平板SN方法的程序，可以广泛应用于反应堆中中子通量密度的计算。(The program of one dimensional flat SN method)
- 2017-12-29 21:10:48下载
- 积分：1
-
20041214085228_vczx_RPG
一个国产RPG游戏 详细讲解RPG游戏的开发过程，还有源码，全是Win32的,大家一起学一下吧！(a homemade RPG elaborate on the development process, source code, all of the Win32, we learn together about!)
- 2004-12-20 18:08:32下载
- 积分：1
-
计01-8班 1号 王大鹏
我的网页制作，其中包含了具体代码，和美观的界面，有兴趣者可下载。(my beautiful web which includes codes)
- 2005-05-15 08:18:22下载
- 积分：1
-
lisanduishu
设p是素数，a是p的本原根，即a1,a2,a3,…,ap-1在mod p下产生1到p-1的所有值，所以对任何b属于{1,…,p-1},有唯一的i属于{1,…,p-1}使得ai mod p 等于p。称i为模p下以a为底b的离散对数。(P is a prime number based, a is the primitive root p, that is, a1, a2, a3, ..., ap-1 in the mod p under 1 to p-1 for all values, so for any b belongs to (1, ..., p-1), there are only i belong to (1, ..., p-1) makes ai mod p equivalent to p. Said i was under the modulus p to a for b at the end of the discrete logarithm.)
- 2009-06-16 17:44:18下载
- 积分：1
-
31701012836
说明： C++编写的简单分数类（包含复制，约分，四则运算等）(Simple fraction classes written in C++ (including duplication, reduction, four operations, etc.))
- 2019-06-11 12:01:16下载
- 积分：1
