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ZDJCPro
织带机监测系统的上位机软件。RS-485总线，类MODBUS协议。(Ribbon Machine Monitoring System for PC software. RS-485 bus, types of MODBUS protocol.)
- 2008-05-01 16:30:13下载
- 积分：1
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mcma
一个CMA算法程序，可以对CMA算法进行一些仿真研究(A CMA algorithm procedures, CMA algorithm can carry out some simulation studies)
- 2008-03-12 10:26:29下载
- 积分：1
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16QAM
说明： 这是16QAM的仿真，带GUI界面，很好用的。(This is 16QAM simulation, with GUI interface, very useful.)
- 2020-07-02 12:20:01下载
- 积分：1
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sellmeier_
Sellmeier index calculation
- 2012-05-08 19:30:35下载
- 积分：1
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MMSE_T_F
实现时域与频域均衡MMSE方法的比较 采用64QAM调制(Comparison of the time domain and frequency domain equalization MMSE method)
- 2021-03-24 08:39:15下载
- 积分：1
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OPC客户端远程服务器
OPC客户端源码，可同时连接局域网内的多个OPC服务器
MFC带界面版(OPC client source code, which can connect multiple OPC servers in LAN at the same time
MFC with Interface Edition)
- 2021-01-06 21:28:54下载
- 积分：1
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pcsc3_v2.01.09
PCSC APDU specification.
- 2011-11-07 19:53:52下载
- 积分：1
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CA_CFAR
仿真了恒虚警的平均单元算法，给出仿真结果，同时分析了不同窗口数对虚警率和检测率的影响，并写了详细的注释(The constant false alarm average cell algorithm is simulated, and the simulation results are given. Meanwhile, the influence of different window numbers on false alarm rate and detection rate is analyzed, and detailed annotations are written.)
- 2017-12-05 13:36:59下载
- 积分：1
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mimo-with-sumrate-analysis
MIMO systems with efficient sum rate analysis
- 2013-08-27 17:26:54下载
- 积分：1
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2
说明： 2. 关于无线信道的多普勒谱，请回答以下问题：
(1) 在某些无线信道中，多普勒频移会引起无线信道输出信号的混叠。请描述产生混叠的各种原因；
(2) 无线信道中的多普勒谱有一种经典谱(classic spectrum)，请解释产生这种谱形状的机理；
(3) 请用Simulink工具编写代码(S-Function方式)，产生一单径瑞利信道，其多普勒谱为经典谱，其中移动速率为120km/h。并请描述：自己用计算机产生的经典谱是正确的依据。(2. Regarding the doppler spectrum of the wireless channel, please answer the following questions:
(1) in some wireless channels, doppler frequency shift will cause aliasing of the output signals of the wireless channel.Describe the various causes of aliasing;
(2) there is a classic spectrum in the doppler spectrum in the wireless channel, please explain the mechanism of producing this spectrum shape;
(3) please use Simulink tool to write code (s-function mode) to generate a single-path Rayleigh channel, whose doppler spectrum is the classical spectrum, in which the moving rate is 120km/h.And please describe: your own computer generated classical spectrum is the correct basis.)
- 2021-01-23 19:48:44下载
- 积分：1
