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estimation原

于 2021-01-24 发布

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下载积分: 1 下载次数: 3

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代码说明：

说明：能够计算IEEE14节点和IEEE30节点的状态估计(It can calculate the state estimation of IEEE14 node and IEEE30 node)

文件列表：

bbusppg.m, 430 , 2008-11-26
busdatas.m, 3704 , 2008-12-08
linedatas.m, 4529 , 2008-11-26
pol2rect.m, 388 , 2017-07-23
rect2pol.m, 377 , 2017-07-23
wls.m, 8211 , 2020-10-23
ybusppg.m, 1371 , 2017-07-23
zdatas.m, 8315 , 2008-12-04

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particle_method
implementation of the particle method, can be used for segmentation purposes.

2010-07-21 17:44:42下载

积分：1
sourcefile
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2009-12-10 20:59:22下载

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randgen(mu,mu1,mu2,cov1,cov2,cov3) = Random generation of Gaussian Samples in d-dimensions where d = 2 mu, mu1, mu2 = (x,y) coordinates(means) that the gaussian samples are centered around cov1, cov2, cov3 are the covariance matrices and will vary changing the shape of the distribution, example: cov = sigma^2*Identity Matrix, where sigma^2 = a scalar N = the number of gaussian samples used are provided as user input, A test set of N/2 and a training set of N/2 gaussian samples is also generated Output is directed to the command window and a plot of the distributions are generated

2011-02-09 18:52:20下载

积分：1
huisetu
说明：应用于各种雾天条件下对图像进行雾去除，可以得到清晰无雾的效果图，是一个不错的图像恢复工具(a method of haze removal,we can gain a haze-free image)

2011-03-18 21:04:46下载

积分：1
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image sccaling. sccaling the image rd blue and green. its not good dont download

2013-09-15 23:07:05下载

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chap6
Matlab图像处理实例详解第六章源码，欢迎大家下载学习，很好很强哟！！(Detailed examples Matlab image processing Chapter VI source, welcome to download the study, very good yo! !)

2013-11-07 18:10:34下载

积分：1
iterative_policy_Evaluation
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2012-10-29 05:21:42下载

积分：1
insdem06
inertial navigation system 2

2008-01-09 19:36:56下载

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YTY_GA_Final
To find the largest fitness value and its location 寻找最大适应性及相应的位置！Population N=50；crossover bits=n/2 (half of bits of an individual) with random locations，mutation bits = 4 种群数 N=50，交换位数= n/2, 即个体位数的一半，且位置随机；变异位数统一取为4； Nc=20，28，36，44，individuals for crossover(交换的个数)。Nm=1，5，10，15， individuals for mutation(变异的个数)。(To find the largest fitness value and its location to find the location of the maximum adaptability and the corresponding! Population N = 50 crossover bits = n/2 (half of bits of an individual) with random locations, mutation bits = 4 population size N = 50, exchange digits = n/2, ie half of the median individual, and random position variation is taken as unity median 4 Nc = 20,28,36,44, individuals for crossover (exchange number). Nm = 1,5,10,15, individuals for mutation (the number of variations.))

2010-12-27 21:23:27下载

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program
维纳噪声抑制；实验分析；实验结果及分析；利用信号之间的相关性进行信号估计，从而将噪声滤除(Wiener noise suppression Experimental analysis The experimental results and analysis Using the signal signal to estimate the association between, to filter out noise )

2013-07-28 17:29:33下载

积分：1

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estimation原

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