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抽奖程序 flash源码下载
抽奖程序 flash源码下载
- 2014-01-02下载
- 积分：1
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计算机机房管理
计算机机房管理，计算机机房管理该软件能控制机房的所有电脑的关机，重启，注销，唤醒，然后监控它们各自的屏幕。老师可以发通知，同学们可以互相聊天。
- 2022-03-09 16:37:37下载
- 积分：1
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projectManage
软件项目管理优秀文档，包含费用管理，成本管理，进度管理等等(Excellent project management software documentation, including cost management, cost management, schedule management, etc.)
- 2010-05-31 12:41:36下载
- 积分：1
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指纹识别算法源代码
指纹图像增强、求方向图、二值化、细化、特征提取、特征匹配等算法的c语言源程序，还有实例演示，本人千辛万苦才找来的，提供给大家分享。
- 2022-02-09 22:02:18下载
- 积分：1
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LoRa
说明： LoRa PCB及原理图,供软件编写人员阅读,有助于编程.(LoRa's PcbDOC and SchDOC)
- 2021-02-24 16:28:49下载
- 积分：1
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BL75R04
继上次源码开放后，本次把BL芯片信息公开下载，供大家与程序操作
BL75R04SM 是遵从 ISO/IEC15693 无线接口的2Kbit 电子标签芯片。可制作成电子
标签或非接触卡，主要适用于大中型物流、商品防盗防伪、工业控制、门禁系统、军
事跟踪、路桥收费、畜牧养殖、图书文档管理、特种设备和金融票据等领域。具备防
2
冲突功能，读写器能同时快速处理多个芯片。片内2K 位 E PROM，分成64block，
每 block 有4 字节的数据存储区，2 个位的块锁存区，管理存储区2 block ，全球唯一
的64 位标示码。 (BL75R04SM 2 K bit EEPROM radio frequency identification
Rf interface fully comply with ISO15693 standards
This program can be more data data and operation
BL75R04SM is follow ISO/IEC15693 wireless interface Kbit electronic tag 2 chip. Can be made into electronic
Tag or the contact card, mainly is suitable for the large and medium-sized logistics, commodity anti-theft security, industrial control, access control system, the army
Things tracking, road, bridge charges, animal husbandry and breeding, books document management, special equipment and financial instruments, etc. Have the
2
Conflict, literacy can at the same time the function DuoGe rapid processing chip. Within 2 K bit E of PROM, which divided into 64,
Every four bytes of data which storage area, two bits of the latch area, the area of storage management, the only global which 2
A mark of 64 yards.
)
- 2011-06-29 14:08:41下载
- 积分：1
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IIC-OLED
说明： stm32f429 iic oled mdk环境(Stm32f429 IIC OLED MDK environment)
- 2020-06-16 02:40:02下载
- 积分：1
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0610210081
说明： 编程实现下面的窗口程序。窗口名称是“My_Windows”，窗口具有最小化、最大化、关闭按钮，窗口的位置和大小可以随意调整。当单击窗口标题栏的最左边时出现系统菜单。
(Programming procedures for the following window. Window name is )
- 2008-10-13 09:17:28下载
- 积分：1
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ForK1
我们的目的是将一个分数拆分成若干个分子是1分母是正整数的分数之和的形式。例如2/3可以拆分成1/2+1/6的形式。这里不考虑顺序，比如1/6+1/2和1/2+1/6相同。
输入p, q, a, n, 其中p/q为分数，对这个分数进行拆分，要求拆分的分数个数不能多于n个，所有分母的乘积不能大于a。求有多少种拆分方法?
输入：最多200组数据。在每行中都有四个数分别表示p, q, a, n，之间以空格隔开，并且满足p,q<=800，a<=12000，n<=7，最后以四个0做为输入的结束。
输入示例:
2 3 120 3
2 3 300 3
0 0 0 0
输出示例:
4
7
(Our aim is to split a fraction into a number of elements is a denominator is a positive integer fraction of the sum of form. For example, 2/3 can be split into 1/2+1/6 form. Not considered here, the order, such as 1/6+1/2 and 1/2+1/6 of the same. Input p, q, a, n, where p/q as a fraction of this split scores require no more than the number of split points n-all the product of the denominator can not be larger than a. How many kinds of demand split method? Input: Up to 200 sets of data. In each line has four numbers indicate the p, q, a, n, separated by a space between, and meet the p, q < = 800, a < = 12000, n < = 7, the end, four 0 as the input end. Input Example: 2,312,032,330,030,000 sample output: 47)
- 2009-11-12 09:54:17下载
- 积分：1
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LAStools
说明： lastools工具，利用lastools工具可以將las文件轉換類型，並且可以在potree中使用(the tool of lastools)
- 2020-06-23 11:00:02下载
- 积分：1
