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GSO算法matlab代码
说明: 萤火虫算法的matlab示例代码,只适用于求极大值(极小值可转化为求极大值)(Firefly algorithm matlab sample code, only applicable to the maximum (minimum can be converted to the maximum))
- 2020-04-13 19:27:45下载
- 积分:1
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earlylate 计算模拟
%
%sim_sym_sync_earlylate.m-早期晚采样时间控制
公园由编程 %
关闭所有
全部清除
%******************** Preparation part *************************************
KC = 1 ;%1/0 或不定时恢复
Ns = 80 ;%符号时间每样本的次数
Ts = 1 ;
T = Ts/Ns ;%符号/采样时间
延迟 = 3 ;%的延迟符号次数的超限筛选器
rof = 0.5 ;滚 %因素
筛选器初始化 %* * * * * *
%平方米根提出余弦值过滤与升频的 Ns?P6.1(h)
Fd = 1/Ts;
Fs = Fd * Ns ;
SRRC_filter = rcosine(Fd,Fs,"fir/sqrt",rof,Delay) ;
[g,tg] = rcosflt([1],Fd,Fs,"filter",SRRC_filter);%和建会筛选与升频
g = g." ;
吴 = length(g) ;%信道响应和它的长度
h = fliplr(g) ;%脉冲响应的 RCVR 匹配基带中的筛选器
衰减计算 %* * * * * *
Es = 1;
SNRbdB = 100 ;
b = 1 ;
pobet = prob_error(SNRbdB,"PSK",b,"bit") ;
SNRb = 10^(SNRbdB/10) ;
N0 = 2 *(Es/b)/SNRb ;
sigma2 = N0/2 ;
sgmsT = sqrt(sigma2/T) ;
dT = Ts/2 ;
dTN = ceil(dT/T) ;
三
- 2022-01-26 06:18:14下载
- 积分:1
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demo_rbpf_gauss
从国外网站下载的,粒子滤波演示程序,程序简单易懂(Website from abroad, the particle filter demo program, the program easy-to-read)
- 2008-01-07 20:30:21下载
- 积分:1
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New-WinRAR-ZIP-archive
This file includes matlab source code for the Uncoded QPSK + Coded QPSK with Viterbi (Hard decesion) decoder.
- 2014-09-04 21:36:40下载
- 积分:1
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sar的bp算法
说明: 针对聚束sar的bp高分辨率成像算法仿真(Simulation of BP high resolution imaging algorithm for spotlight SAR)
- 2021-04-19 22:08:50下载
- 积分:1
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jdqr
程序实现雅克比.戴维逊的QR分解,希望有用到的!(Program to achieve Jacobi. Davidson QR decomposition, hope to be useful!)
- 2011-09-29 08:38:09下载
- 积分:1
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毕设时的定功率单环控制
采用热核构造权重,外文资料里面的源代码,能量谱分析计算,光纤陀螺输出误差的allan方差分析,相控阵天线的方向图(切比雪夫加权),一种噪声辅助数据分析方法。
- 2023-04-25 09:50:03下载
- 积分:1
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RobustSharpeTest
Test whether the difference of two Sharpe ratios is statistically significant. No normality assumption needed, the bootstrap approach approximates the data-generating process.
- 2009-10-13 02:59:19下载
- 积分:1
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pca01
pca, algoritmo pca en matlab
- 2010-01-26 14:09:12下载
- 积分:1
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yuanma
说明: 求解方程-u"(x)+u(x)=exp(x)*(sin(x)-2*cos(x))两点边值问题(Solve the equation-u " (x)+ u (x) = exp (x)* (sin (x)-2* cos (x)) Boundary Value Problems)
- 2010-04-30 09:13:41下载
- 积分:1