登录
首页 » c++ » 串口OPC

串口OPC

于 2022-03-09 发布 文件大小:28.22 MB
0 113
下载积分: 2 下载次数: 1

代码说明:

实现串口数据采集和发送,可以材料消防串口数据,也可以自己改写,进行采集其他串口类型数据

下载说明:请别用迅雷下载,失败请重下,重下不扣分!

发表评论

0 个回复

  • STM32-control-CC1101
    STM32控制CC1101发送接收的源代码,可通过串口调试工具查看接收到的数据。(STM32 control CC1101 transmit and receive the source code, can be received through the serial port debugging tool to view the data.)
    2020-11-09 11:19:47下载
    积分:1
  • SENDMSM
    利用短信猫发短信,通用源码,共享大家学习(SEND SMS)
    2013-10-14 10:40:51下载
    积分:1
  • main
    8051f300 128码 识别程序,对特殊128码进行过滤(8051f300 128 code identification procedures, a special filter Code 128)
    2011-05-17 22:06:36下载
    积分:1
  • 0
    说明:  1. 阅读C#编程方面的书籍与资料。 2. 使用窗体界面、控件编程。 3. 把图像数据读取到变量或数组中。(1. read C# programming books and materials. 2. use form interface and control programming. 3. read image data into variables or arrays.)
    2018-10-08 20:55:05下载
    积分:1
  • 电子银行离线地图查找ATM机
    电子银行离线地图查找ATM机
    2015-06-16下载
    积分:1
  • OLED
    oled显示屏测试源代码,可显示姓名学号(OLED display test source code, can display name and student number)
    2020-06-23 15:00:01下载
    积分:1
  • double-qga
    双链量子遗传算法双链量子遗传算法双链量子遗传算法双链量子遗传算法双链量子遗传算法双链量子遗传算法(DOUBLE qGADOUBLE qGADOUBLE qGADOUBLE qGADOUBLE qGADOUBLE qGADOUBLE qGA)
    2011-09-18 15:24:00下载
    积分:1
  • C_EDIT
    Ed Reams Red 开发的文本编辑(Ed Reams Red development of a text editor)
    2005-02-23 10:51:43下载
    积分:1
  • agentga
    关于多智能体遗传算法优化神经网络的MATLAB程序(On multi-agent genetic algorithm to optimize the MATLAB neural network program)
    2010-06-17 09:07:38下载
    积分:1
  • combine---two-binary-trees-
    This is a small program to create indexs for two binary trees and combine them to a new 003 * index tree and output the new tree,the second tree only has the left child tree then 004 * if the first tree has no left child tree,insert the second tree into the first tree as 005 * its left child and if the first tree has the left child tree,then insert the first tree 006 * into the second tree as its left child. (This is a small program to create indexs for two binary trees and combine them to a new 003* index tree and output the new tree, the second tree only has the left child tree then 004* if the first tree has no left child tree, insert the second tree into the first tree as 005* its left child and if the first tree has the left child tree, then insert the first tree 006* into the second tree as its left child.)
    2012-06-11 16:16:55下载
    积分:1
  • 696516资源总数
  • 106658会员总数
  • 16今日下载