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Nxp_Template
LPC1788基础工程文档,特别干净,目录设计合理,结构清晰,非常合适在此基础上开始增加自己的代码。已在此基础上完成几个项目的开发!!!(LPC1788-based engineering documentation, especially clean, catalog rational design, clear structure, very appropriate on this basis, began to increase their own code. Has completed the development of several projects based on this! ! !)
- 2014-03-26 15:47:25下载
- 积分:1
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DSA数字签名
dsa数字签名
系统功能需求:
1.对文件进行签名,生成一个独立于原文的签名文件;
2.可以对文件进行签名,在文件后追加签名信息;
3.具有密钥管理的功能,比如密钥的生成、导入、导出;
4.可以对word文档实施操作,对word文档的内容进行签名;
5.能够比对已经实施的签名,防止进行重复的签名,以防止重放攻击;
6.可以对已经签名的文件进行单独的源文件和签名信息的分离操作。(DSA digital signature
System functional requirements:
1. Sign the document and generate a signature file independent of the original text.
2. The document can be signed and the signature information can be added after the document.
3. It has the function of key management, such as key generation, import and export.
4. Word documents can be operated and the contents of Word documents can be signed.
5. Ability to compare existing signatures and prevent duplicate signatures to prevent replay attacks;
6. It is possible to separate the source file from the signature information of the signed file.)
- 2021-01-06 21:18:54下载
- 积分:1
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AT芯片存储开机次数
利用at芯片存储数据,具有掉电不丢失。模拟我们手机开机关机多少次。(Using the at chip to store data, there is no loss of power loss. Simulate how many times our phone is turned off.)
- 2018-09-07 16:37:14下载
- 积分:1
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CurveLab-2.1.3 - 副本
说明: 可用于图像处理的曲波变换程序包,包括MATLAB和C++实现(Curve Wave Transform Package for Image Processing, Including MATLAB and C++ Implementation)
- 2020-06-24 02:20:02下载
- 积分:1
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AutoCAD VBA开发精彩实例教程(1-10章实例源码下载) VBA_For_AutoCAD
AutoCAD VBA开发精彩实例教程(1-10章实例源码下载) VBA_For_AutoCAD
- 2014-06-04下载
- 积分:1
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CopyHunter
文件拷贝猎手,能进行断点续传功能,方便局域网内部的共享文件拷贝!(File copy hunter, capable of HTTP functionality, easy to share the internal LAN file copy!)
- 2011-08-22 00:19:30下载
- 积分:1
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新浪网盘小爬虫
新浪网盘小爬虫,批量爬下新浪网盘的文件。。。。通过c#实现的,希望能给您一个提示。。。
- 2022-06-12 18:55:13下载
- 积分:1
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GC4016
数字下变频器GC4016及其在软件无线电中的应用(GC4016 digital down-converter and its application in software radio)
- 2009-10-28 11:26:42下载
- 积分:1
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11087 统计逆序对
Description
设a[0…n-1]是一个包含n个数的数组,若在i<j的情况下,有a[i]>a[j],则称(i, j)为a数组的一个逆序对(inversion)。
比如 <2,3,8,6,1> 有5个逆序对。请采用类似“合并排序算法”的分治思路以O(nlogn)的效率来实现逆序对的统计。
一个n个元素序列的逆序对个数由三部分构成:
(1)它的左半部分逆序对的个数,(2)加上右半部分逆序对的个数,(3)再加上左半部分元素大于右半部分元素的数量。
其中前两部分(1)和(2)由递归来实现。要保证算法最后效率O(nlogn),第三部分(3)应该如何实现?
此题请勿采用O(n^2)的简单枚举算法来实现。
并思考如下问题:
(1)怎样的数组含有最多的逆序对?最多的又是多少个呢?
(2)插入排序的运行时间和数组中逆序对的个数有关系吗?什么关系?
输入格式
第一行:n,表示接下来要输入n个元素,n不超过10000。
第二行:n个元素序列。
输出格式
逆序对的个数。
输入样例
5
2 3 8 6 1
输出样例
5(Set a[0... N-1] is a n array containing n numbers. If there is a [i] > a [j] i n the case of I < j, then (i, j) is a n inversion pair of a array.
For example, <2,3,8,6,1> has five reverse pairs. Please use the idea of "merge sorting algorithm" to achieve the statistics of inverse pairs with O (nlogn) efficiency.
The number of inverse pairs of a sequence of n elements consists of three parts:
(1) The number of reverse pairs in the left half, (2) the number of reverse pairs in the right half, (3) the number of elements in the left half is greater than that in the right half.
The first two parts (1) and (2) are implemented by recursion. To ensure the final efficiency of the algorithm O (nlogn), how should the third part (3) be implemented?
Do not use O (n ^ 2) simple enumeration algorithm to solve this problem.)
- 2019-01-07 23:52:06下载
- 积分:1
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Atmel-ATSHA204A-Library
说明了204加密芯片的应用,极大地方便了使用这了解该芯片的使用和编程。(The application of 204 encryption chip is explained.)
- 2017-09-20 22:08:22下载
- 积分:1